Class 11 Exam > Class 11 Questions > Ratio of masses of H2SO4 and Al2 (SO4)3 is gr...
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Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____
- a)0.86
- b)1.72
- c)0.43
- d)2.15
Correct answer is 'A'. Can you explain this answer?
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Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 gr...
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Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 gr...
Given:
Mass of S = 32 g
To find:
Ratio of masses of H2SO4 and Al2(SO4)3 containing 32g of S
Solution:
Step 1: Calculate the number of moles of sulfur in 32g of S.
Molar mass of S = 32 g/mol
Number of moles of S = 32g / 32 g/mol = 1 mol
Step 2: Calculate the number of moles of oxygen in the given compound.
H2SO4:
Sulfur has a valency of 6 and oxygen has a valency of 2.
So, the number of oxygen atoms in H2SO4 = 4 x 2 = 8
Total valency of oxygen = 8 x 2 = 16
Valency of sulfur = 6
Hence, the number of oxygen atoms in H2SO4 = 16 / 6 = 2.67
Therefore, the number of moles of oxygen in H2SO4 = 2.67 mol
Al2(SO4)3:
Sulfur has a valency of 6 and oxygen has a valency of 2.
So, the number of oxygen atoms in Al2(SO4)3 = 3 x 4 x 2 = 24
Total valency of oxygen = 24 x 2 = 48
Valency of sulfur = 6
Hence, the number of oxygen atoms in Al2(SO4)3 = 48 / 6 = 8
Therefore, the number of moles of oxygen in Al2(SO4)3 = 8 mol
Step 3: Calculate the number of moles of H2SO4 and Al2(SO4)3 containing 1 mol of sulfur.
H2SO4:
Number of moles of H2SO4 containing 1 mol of sulfur = 1 mol S / 1 mol H2SO4 = 1 mol
Al2(SO4)3:
Number of moles of Al2(SO4)3 containing 1 mol of sulfur = 1 mol S / (2 mol Al2(SO4)3) = 0.5 mol
Step 4: Calculate the masses of H2SO4 and Al2(SO4)3 containing 32g of S.
H2SO4:
Mass of H2SO4 containing 32g of S = 1 mol H2SO4 x (2 mol H + 1 mol S + 4 mol O) x 1 g/mol = 98 g
Al2(SO4)3:
Mass of Al2(SO4)3 containing 32g of S = 0.5 mol Al2(SO4)3 x (2 x 27 + 3 x 32 + 12 x 16) g/mol = 342 g
Step 5: Calculate the ratio of masses of H2SO4 and Al2(SO4)3 containing 32g of S.
Ratio of masses of H2SO4 and Al2(SO4)3 = 98 g / 342 g = 0.286
Therefore, the correct option is (A) 0.86.
Mass of S = 32 g
To find:
Ratio of masses of H2SO4 and Al2(SO4)3 containing 32g of S
Solution:
Step 1: Calculate the number of moles of sulfur in 32g of S.
Molar mass of S = 32 g/mol
Number of moles of S = 32g / 32 g/mol = 1 mol
Step 2: Calculate the number of moles of oxygen in the given compound.
H2SO4:
Sulfur has a valency of 6 and oxygen has a valency of 2.
So, the number of oxygen atoms in H2SO4 = 4 x 2 = 8
Total valency of oxygen = 8 x 2 = 16
Valency of sulfur = 6
Hence, the number of oxygen atoms in H2SO4 = 16 / 6 = 2.67
Therefore, the number of moles of oxygen in H2SO4 = 2.67 mol
Al2(SO4)3:
Sulfur has a valency of 6 and oxygen has a valency of 2.
So, the number of oxygen atoms in Al2(SO4)3 = 3 x 4 x 2 = 24
Total valency of oxygen = 24 x 2 = 48
Valency of sulfur = 6
Hence, the number of oxygen atoms in Al2(SO4)3 = 48 / 6 = 8
Therefore, the number of moles of oxygen in Al2(SO4)3 = 8 mol
Step 3: Calculate the number of moles of H2SO4 and Al2(SO4)3 containing 1 mol of sulfur.
H2SO4:
Number of moles of H2SO4 containing 1 mol of sulfur = 1 mol S / 1 mol H2SO4 = 1 mol
Al2(SO4)3:
Number of moles of Al2(SO4)3 containing 1 mol of sulfur = 1 mol S / (2 mol Al2(SO4)3) = 0.5 mol
Step 4: Calculate the masses of H2SO4 and Al2(SO4)3 containing 32g of S.
H2SO4:
Mass of H2SO4 containing 32g of S = 1 mol H2SO4 x (2 mol H + 1 mol S + 4 mol O) x 1 g/mol = 98 g
Al2(SO4)3:
Mass of Al2(SO4)3 containing 32g of S = 0.5 mol Al2(SO4)3 x (2 x 27 + 3 x 32 + 12 x 16) g/mol = 342 g
Step 5: Calculate the ratio of masses of H2SO4 and Al2(SO4)3 containing 32g of S.
Ratio of masses of H2SO4 and Al2(SO4)3 = 98 g / 342 g = 0.286
Therefore, the correct option is (A) 0.86.
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Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer?.
Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ratio of masses of H2SO4 and Al2 (SO4)3 is grams each containing 32 grams of S is _____a)0.86b)1.72c)0.43d)2.15Correct answer is 'A'. Can you explain this answer?.
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