Determine the turning radius of taxiway for an aircraft wheel base of 30m Tread of main loading gear is 6m Design turning speed is 50kmph Width of taxiway pavement is 22.5m coefficient of friction 0.13m using Horonjeff equationa)150.5 mb)155.5 mc)105.5 md)NoneCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

Calculation of Turning Radius:

- Given parameters:
- Wheel base (WB) = 30m
- Tread of main loading gear (T) = 6m
- Design turning speed = 50 kmph
- Width of taxiway pavement (W) = 22.5m
- Coefficient of friction (μ) = 0.13

Horonjeff equation:
$$ R = \frac{WB}{2} + \frac{W^2}{8T} + \frac{T}{2} $$

Calculation:
- Substitute the given values into the equation:
$$ R = \frac{30}{2} + \frac{22.5^2}{8*6} + \frac{6}{2} $$
$$ R = 15 + \frac{506.25}{48} + 3 $$
$$ R = 15 + 10.53125 + 3 $$
$$ R = 28.53125 \approx 28.5m $$

- Convert the design turning speed from kmph to m/s:
$$ 50 km/hr = \frac{50*1000}{3600} m/s \approx 13.89 m/s $$

- Calculate the turning radius using the formula:
$$ Radius = \frac{V^2}{g \cdot μ} $$
$$ R = \frac{13.89^2}{9.81 \times 0.13} $$
$$ R = \frac{192.9721}{1.2733} \approx 151.61m $$

Therefore, the turning radius of the taxiway for an aircraft with a wheel base of 30m is approximately 151.61m, which is closest to option B (155.5m).

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