How many three digit odd numbers can be formed by using the digits 5,6,7,8 if the repetition of digits is allowed?a)64b)32c)24d)None of theseCorrect answer is 'B'. Can you explain this answer?

Question

Answer

The unit place can b filled in 2 ways...bcz asked to find 3digit odd numbers frm 5,6,7,8...the other two places can b filled in 4 ways as repetition is allowed...=>>_ _ _ (5,7)......| | |......* * *......4 4 2Total 3 digit odd numbers =4×4×2=32 ... HOPE U GOT IT...

Answer

Unit place can be filled by any one of 5 or 7 and last 2nd and last 3rd place will filled by all due to repetition so
4*4*2= 32

Answer

Unit's place can be filled in 2 ways... Decimal place can be filled in 4 ways.... Hundred's place can be filled in 4 ways...  ===> 4*4*2 = 32

Answer

Ttl ways r....4*4*2 ....as last can only fill by 5 n 7...hence ttl ways ....32

Answer

To find the number of three-digit odd numbers that can be formed using the digits 5, 6, 7, and 8 with repetition allowed, we need to consider the possible combinations of these digits.

1. Find the possible choices for each digit:
- Hundreds digit: Since it cannot be zero, we have 4 choices (5, 6, 7, 8).
- Tens digit: Any of the four digits (5, 6, 7, 8) can be chosen.
- Units digit: We need an odd number, so only 5 and 7 can be chosen.

2. Multiply the number of choices for each digit:
- Number of choices for the hundreds digit = 4
- Number of choices for the tens digit = 4
- Number of choices for the units digit = 2

3. Multiply the number of choices for each digit together:
Number of three-digit odd numbers = 4 × 4 × 2 = 32

Therefore, the correct answer is option B) 32.

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