An object of mass 1 kg travelling in a straight line with a velocity o...
Mass of the object, m1 = 1 kgVelocity of the object, u1 = 10ms^-1Mass of the wooden block, m2 =5 kgVelocity after collision, u2 =0 m/sLet v be the velocity of the combined object after the collisionThat is, Total momentum just before the impact is, m1u1 + m2u2 = 1 x 10 + 5 x 0 = 10 kg ms^-1 Total momentum just after the impact is, (m1 + m2) v = (1+5)v = 6v kg ms^-1 Using the law of conservation of momentum, 6v = 10 => v = 10/6 = 5/3 = ms^-1 Therefore, Total momentum just after the impact= 6 x 5/3 = 10 ms^-1.
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An object of mass 1 kg travelling in a straight line with a velocity o...
Total Momentum Before the Impact:
The total momentum before the impact can be calculated by summing up the individual momenta of the objects involved. Momentum is defined as the product of an object's mass and its velocity.
Given:
Mass of object 1 (m1) = 1 kg
Velocity of object 1 (v1) = 10 m/s
Mass of wooden block (m2) = 5 kg
Velocity of wooden block (v2) = 0 m/s (as it is stationary)
The momentum of object 1 (p1) is given by:
p1 = m1 * v1
= 1 kg * 10 m/s
= 10 kg⋅m/s
The momentum of the wooden block (p2) is given by:
p2 = m2 * v2
= 5 kg * 0 m/s
= 0 kg⋅m/s
Therefore, the total momentum before the impact is the sum of p1 and p2:
Total Momentum Before the Impact (p_total) = p1 + p2 = 10 kg⋅m/s + 0 kg⋅m/s = 10 kg⋅m/s
Total Momentum After the Impact:
After the impact, the two objects stick together and move as a single unit. Let's denote the velocity of the combined objects as v_combined.
Using the principle of conservation of momentum, the total momentum after the impact (p_total') should be equal to the total momentum before the impact (p_total).
The total mass after the impact (m_total') is the sum of the individual masses:
m_total' = m1 + m2
= 1 kg + 5 kg
= 6 kg
Therefore, the total momentum after the impact (p_total') is given by:
p_total' = m_total' * v_combined
Since the objects stick together, their velocities become the same. So we can write:
v_combined = v1' = v2'
Substituting the values, we have:
10 kg⋅m/s = 6 kg * v_combined
Simplifying, we find:
v_combined = 10 kg⋅m/s / 6 kg
Hence, the velocity of the combined objects after the impact is:
v_combined = 5/3 m/s
Summary:
- The total momentum before the impact is 10 kg⋅m/s.
- The velocity of the combined objects after the impact is 5/3 m/s.
- The principle of conservation of momentum states that the total momentum of a system remains constant if no external forces act on it.
- In this scenario, the momentum of the system is conserved as the objects stick together and move with a common velocity after the impact.
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