A ball of mass 0.5 kg is thrown up with velocity of 15m/s.Find it's PE at highest point.(g=10m/s2)?

Question

Answer

Calculating Potential Energy at the Highest Point

- Given data:
- Mass of the ball (m) = 0.5 kg
- Initial velocity (u) = 15 m/s
- Acceleration due to gravity (g) = 10 m/s^2

- Step 1: Calculate the maximum height reached by the ball.
- Using the kinematic equation: v^2 = u^2 + 2as
- At the highest point, the final velocity (v) becomes 0 m/s.
- Therefore, 0 = (15)^2 - 2 * 10 * h
- Solving for h, we get h = 11.25 m

- Step 2: Calculate the potential energy at the highest point.
- Potential Energy (PE) = mgh
- Substitute the values of mass (m = 0.5 kg), height (h = 11.25 m), and acceleration due to gravity (g = 10 m/s^2) into the formula.
- PE = 0.5 * 10 * 11.25
- PE = 56.25 J

Therefore, the potential energy of the ball at its highest point is 56.25 Joules. This energy represents the ability of the ball to do work due to its position relative to the reference point, which in this case is the ground. This calculation helps us understand the energy transformation that occurs as the ball moves against gravity.

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