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Electric field intensity is equal to
- a)time rate of change of potential
- b)minimum rate of change of potential with distance
- c)maximum rate of change of potential with distance
- d)none of the above
Correct answer is 'C'. Can you explain this answer?
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Most Upvoted Answer
Electric field intensity is equal toa)time rate of change of potential...
Explanation:
Electric field intensity (E) is defined as the force per unit charge acting on a test charge placed in an electric field. It is a vector quantity and is denoted by the symbol E.
Electric field intensity is related to potential difference or voltage (V) between two points in an electric field. The potential difference between two points is defined as the work done per unit charge in moving a test charge from one point to another in an electric field.
The rate of change of potential difference with distance is known as the electric field gradient or the electric field strength. It is denoted by the symbol E.
The maximum rate of change of potential difference with distance is known as the electric field intensity. It is denoted by the symbol E and is given by the formula:
E = -dV/dr
where dV/dr is the rate of change of potential difference with distance.
Therefore, the correct answer is option C, i.e. maximum rate of change of potential difference with distance.
Electric field intensity (E) is defined as the force per unit charge acting on a test charge placed in an electric field. It is a vector quantity and is denoted by the symbol E.
Electric field intensity is related to potential difference or voltage (V) between two points in an electric field. The potential difference between two points is defined as the work done per unit charge in moving a test charge from one point to another in an electric field.
The rate of change of potential difference with distance is known as the electric field gradient or the electric field strength. It is denoted by the symbol E.
The maximum rate of change of potential difference with distance is known as the electric field intensity. It is denoted by the symbol E and is given by the formula:
E = -dV/dr
where dV/dr is the rate of change of potential difference with distance.
Therefore, the correct answer is option C, i.e. maximum rate of change of potential difference with distance.
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Community Answer
Electric field intensity is equal toa)time rate of change of potential...
We bring a charge from infinity to a point which is maximum . and so discuss the electric field intensity at any point is maximum. hence it is max. rate of change of potential with distance
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Electric field intensity is equal toa)time rate of change of potentialb)minimum rate of change of potential with distancec)maximum rate of change of potential with distanced)none of the aboveCorrect answer is 'C'. Can you explain this answer?
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