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Find the point of the local maximum of the function
f(y) = y + (1/y), y ≠ 0 
  • a)
    y = 1
  • b)
    y = -2
  • c)
    y = -1
  • d)
    y = 2
Correct answer is option 'C'. Can you explain this answer?
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Find the point of the local maximum of the functionf(y) = y + (1/y), y...
f(y) = y + (1/y), y ≠ 0 
Differentiate w.r.t. y

Sign scheme for f'(y) is

Using the first derivative test
As f'(y) changes its sign positive to negative at y = -1, therefore, f(y) has a local maximum at y = -1.
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Find the point of the local maximum of the functionf(y) = y + (1/y), y ≠ 0a)y = 1b)y = -2c)y = -1d)y = 2Correct answer is option 'C'. Can you explain this answer?
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