A mixture of gas "X"(mol wt. 16) and gas Y(mol wt. 28) in the mole rat...
For mixture in mole ratio a:b --> (a x 16 + b x 28) /(a+b)= 20So, 16 a + 28 b = 20 a + 20 b4a = 8b So, a = 2b, a/b = 2Now, for mole ratio b:a -->(16b + 28a)/b+a = (16 + 28a/b)/(1+a/b)Mean molecular weight = 16 + 28 x 2/1+2 = 24
This question is part of UPSC exam. View all Class 11 courses
A mixture of gas "X"(mol wt. 16) and gas Y(mol wt. 28) in the mole rat...
Explanation:
Given Information:
- Gas X has a molar weight of 16.
- Gas Y has a molar weight of 28.
- The gases are mixed in the mole ratio a:b.
- The mean molecular weight of the mixture is 20.
Calculating the Mean Molecular Weight:
- Let the number of moles of gas X be 'a' and the number of moles of gas Y be 'b'.
- The mean molecular weight of the mixture can be calculated using the formula:
Mean molecular weight = (a*16 + b*28) / (a + b)
- Given that the mean molecular weight is 20, we can write the equation as:
20 = (16a + 28b) / (a + b)
Calculating the Mean Molecular Weight in the ratio b:a:
- If the gases are mixed in the mole ratio b:a, the new equation will be:
20 = (16b + 28a) / (a + b)
- Solving this equation will give us the mean molecular weight of the mixture when the gases are mixed in the ratio b:a.
By solving the above equation, you can find the mean molecular weight of the mixture when gases X and Y are mixed in the mole ratio b:a under identical conditions.
A mixture of gas "X"(mol wt. 16) and gas Y(mol wt. 28) in the mole rat...
A uniform glass tube of 100 cm length is connected to a bulb containing hydrogen at one end and another bulb containing oxygen at the other end at the same temperature and pressure the two gases meet for the first time at the following distance from the oxygen end
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.