Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  Consider the following 3-address code. 1₁ = t... Start Learning for Free
Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.?
Most Upvoted Answer
Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}...


Optimizing Temporary Variables in 3-address code

- Initial 3-address code:
1. t1 = t + e
2. t2 = g + a
3. 3 = 42
4. t4 = b + t2
5. 16 = 4 +

- Analysis:
In the given 3-address code, there are five temporary variables t1, t2, t3, t4, and t5.

- Optimization Technique:
To minimize the number of temporary variables used, we can reuse the existing variables and eliminate unnecessary ones.

- Optimized 3-address code:
1. t1 = t + e
2. t2 = g + a
3. 3 = 42
4. t4 = b + t2
5. 16 = 4 + t2

- Explanation:
1. Instead of creating a new temporary variable for the last assignment (16 = 4 +), we can reuse t2 from the previous assignment.
2. This optimization reduces the total number of temporary variables used in the code.

- Minimum number of temporary variables:
With the optimization, we can minimize the number of temporary variables to four (t1, t2, t4, t5) in the equivalent optimized 3-address code.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.?
Question Description
Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.?.
Solutions for Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? defined & explained in the simplest way possible. Besides giving the explanation of Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.?, a detailed solution for Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? has been provided alongside types of Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? theory, EduRev gives you an ample number of questions to practice Consider the following 3-address code. 1₁ = t + e t_{2}=g+a 3=42 t_{4}=b+t_{2} 16=4+ There are five temporary variables in above code. Find minimum number of temporary variables can be used in the equivalent optimized 3-address code of above code.? tests, examples and also practice Computer Science Engineering (CSE) tests.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev