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Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH)2 is:​
  • a)
    0.0015
  • b)
    0.003
  • c)
    0.0050
  • d)
    0.0075
Correct answer is 'B'. Can you explain this answer?
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Verified Answer
Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH...
0.3 L = 0.3 L of 0.005 M Ba(OH)2
0.3 x 0.005 = 0.0015 moles of Ba(OH)2
It will dissociate into 0.0015 moles of Ba and 2 x 0.0015 = 0.003 moles of OH ions.
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Most Upvoted Answer
Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH...
To determine the number of moles of hydroxide ions in a solution of Ba(OH)2, we need to first calculate the number of moles of Ba(OH)2 using the given information. Then, we can use the stoichiometry of the compound to determine the number of moles of hydroxide ions.

1. Calculate the number of moles of Ba(OH)2:
Given:
Volume of solution = 0.3 L
Concentration of Ba(OH)2 = 0.005 M

Using the formula:
Molarity (M) = moles/volume (L)

Rearranging the formula:
moles = Molarity × volume

moles of Ba(OH)2 = 0.005 M × 0.3 L = 0.0015 moles

2. Calculate the number of moles of hydroxide ions:
The balanced chemical equation for the dissociation of Ba(OH)2 is:
Ba(OH)2 → Ba2+ + 2 OH-

From the equation, we can see that for every mole of Ba(OH)2, we get 2 moles of OH- ions. Therefore, the number of moles of OH- ions is twice the number of moles of Ba(OH)2.

moles of OH- ions = 2 × moles of Ba(OH)2 = 2 × 0.0015 moles = 0.003 moles

Hence, the correct answer is option B) 0.003 moles.

Summary:
- The number of moles of Ba(OH)2 is calculated using the formula Molarity × volume.
- The stoichiometry of the compound is used to determine the number of moles of OH- ions, which is twice the number of moles of Ba(OH)2.
- Therefore, the correct answer is 0.003 moles.
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Community Answer
Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH...
So easy. first break ba(oh)2 Into ions. here u need only oh. Ba(oh)2 ---> 2(oh-) . then find no. of moles of ba(oh)^2 ( no. of moles. = molarity × vol. of Soln. in litre.) then acc. to our eqn., 1 mole of ba(oh)2 gives 2mole oh- ions. so 0.0015 moles of ba(oh)2 will give 2×0.0015 = 0.003 moles pf oh^- :)
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Number of moles of hydroxide ions in 0.3L of 0.005M solution of Ba (OH)2is:​a)0.0015b)0.003c)0.0050d)0.0075Correct answer is 'B'. Can you explain this answer?
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