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Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.
  • a)
    5
  • b)
    6
  • c)
    4
  • d)
    3
  • e)
    7
Correct answer is 'C'. Can you explain this answer?
Verified Answer
Find the first term of an AP whose 8th and 12th terms are respectively...
Solution: 1st Method:
8th term = a+7d = 39 ........... (i)
12th term = a+11d = 59 ........... (ii)
(i)-(ii);

Or, a+7d-a-11d = 39-59; Or, 4d = 20;
Or, d = 5;
Hence, a+7*5 = 39;
Thus, a = 39-35 = 4.
2nd Method (Thought Process): 
8th term = 39;
And, 12th term = 59;
Here, we see that 20 is added to 8th term 39 to get 12th term 59 i.e. 4 times the common difference is added to 39.
So, CD = 20/4 = 5.
Hence, 7 times CD is added to 1st term to get 39. That means 4 is the 1st term of the AP.
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Most Upvoted Answer
Find the first term of an AP whose 8th and 12th terms are respectively...
39=a+7d, 59=a+11d, on solving. 4d=20,so d=5,so 59=a+(11×5), 59=a+55,so a=4.
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Community Answer
Find the first term of an AP whose 8th and 12th terms are respectively...
T8= a +( n-1)d, 39= a + 7d. similarly . 59= a+11d by solving this we get d= 5 ,a= 4 where a is first term and d be the common difference.
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Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.a)5b)6c)4d)3e)7Correct answer is 'C'. Can you explain this answer?
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