A particle is moving along a circle of radius R such that it completes...
1 revolution in 40 seconds
In 1 second it covers = 1/40 revolution
In 140 sec = 1/40 * 140 =7/2 rotation = 3 and half rotation
Then the particle will be on the diametrically opposite end.
Therefore, Displacement = R + R = 2R
A particle is moving along a circle of radius R such that it completes...
Given:
- Particle is moving along a circle of radius R
- It completes one revolution in 40 seconds
- Time = 2 minutes 20 seconds = 140 seconds
To find: Displacement of the particle after 2 minutes 20 seconds
Solution:
- One revolution is completed in 40 seconds
- Therefore, in 1 second, the particle covers 1/40th of the circumference of the circle
- Circumference of a circle = 2πR
- Therefore, in 1 second, the particle covers 2πR/40 distance
- In 140 seconds, the particle covers (2πR/40) x 140 distance
- Simplifying, we get the displacement as (7πR/2) or 3.5πR
- Option B says the displacement is 2R
- This is not equal to (7πR/2) or 3.5πR
- Therefore, option B is incorrect
- Option A says the displacement is 6R
- This is not equal to (7πR/2) or 3.5πR
- Therefore, option A is incorrect
- Option C says the displacement is 4R
- This is not equal to (7πR/2) or 3.5πR
- Therefore, option C is incorrect
- Option D says the displacement is R
- This is not equal to (7πR/2) or 3.5πR
- Therefore, option D is incorrect
- Hence, the correct answer is option B, which says the displacement is 2R.