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HCF of (9000,X)=60 where X is a natural number less than 9000 find the number of possible values of X?
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HCF of (9000,X)=60 where X is a natural number less than 9000 find the...



Analysis:
To find the number of possible values of X, we need to consider the factors of 60 and see how many of these factors are less than 9000.

Factors of 60:
- 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60

Calculations:
Let's analyze each factor to see if it is a valid value for X:
- If X = 1, HCF(9000, 1) = 1 ≠ 60
- If X = 2, HCF(9000, 2) = 2 ≠ 60
- If X = 3, HCF(9000, 3) = 3 ≠ 60
- If X = 4, HCF(9000, 4) = 4 ≠ 60
- If X = 5, HCF(9000, 5) = 5 ≠ 60
- If X = 6, HCF(9000, 6) = 6 ≠ 60
- If X = 10, HCF(9000, 10) = 10 ≠ 60
- If X = 12, HCF(9000, 12) = 12 ≠ 60
- If X = 15, HCF(9000, 15) = 15 ≠ 60
- If X = 20, HCF(9000, 20) = 20 ≠ 60
- If X = 30, HCF(9000, 30) = 30 ≠ 60
- If X = 60, HCF(9000, 60) = 60 = 60

Conclusion:
There is only one possible value of X that satisfies the given condition, which is X = 60. Therefore, there is only 1 possible value of X that meets the criteria.

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HCF of (9000,X)=60 where X is a natural number less than 9000 find the number of possible values of X?
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