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The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 BM. The suitable ligand for this complex is:
- a)CO
- b)NCS-
- c)Ethylenediamine
- d)CN-
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 ...
The magnetic moment of the magnitude 5.9 BM suggest the presence of 5 unpaired electrons in Mn (II). This can be cross verified by putting the value (5) of unpaired electrons in the formulas, μ = √n(n + 2)BM
Thus, the valence electronic configuration of Mn (II) in the complex is
The octahedral homoleptic complex suggest sp3d3-hybridisation in the complex, i.e,
The octahedral homoleptic complex suggest sp3d3-hybridisation in the complex, i.e,
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The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 ...
Explanation:
Magnetic Moment of Mn(II) complex:
- The magnetic moment of an octahedral homoleptic Mn(II) complex is given as 5.9 BM.
- This value indicates the presence of five unpaired electrons in the complex.
Suitable Ligand Choice:
- Out of the given options, NCS- (Thiocyanate) is the most suitable ligand for this Mn(II) complex.
- Thiocyanate is a strong field ligand that leads to high spin complexes with Mn(II).
- The high spin configuration results in the presence of five unpaired electrons in the complex, as indicated by the magnetic moment value of 5.9 BM.
Explanation of other options:
- CO is a weak field ligand and would lead to a low spin complex with Mn(II), which would not match the observed magnetic moment.
- Ethylenediamine is a neutral ligand that does not strongly influence the spin state of the complex, making it less likely to result in a high spin configuration with five unpaired electrons.
- CN- is also a strong field ligand, but it typically forms low spin complexes with Mn(II), which would not align with the observed magnetic moment.
Therefore, the suitable ligand choice for the octahedral homoleptic Mn(II) complex with a magnetic moment of 5.9 BM is NCS-.
Magnetic Moment of Mn(II) complex:
- The magnetic moment of an octahedral homoleptic Mn(II) complex is given as 5.9 BM.
- This value indicates the presence of five unpaired electrons in the complex.
Suitable Ligand Choice:
- Out of the given options, NCS- (Thiocyanate) is the most suitable ligand for this Mn(II) complex.
- Thiocyanate is a strong field ligand that leads to high spin complexes with Mn(II).
- The high spin configuration results in the presence of five unpaired electrons in the complex, as indicated by the magnetic moment value of 5.9 BM.
Explanation of other options:
- CO is a weak field ligand and would lead to a low spin complex with Mn(II), which would not match the observed magnetic moment.
- Ethylenediamine is a neutral ligand that does not strongly influence the spin state of the complex, making it less likely to result in a high spin configuration with five unpaired electrons.
- CN- is also a strong field ligand, but it typically forms low spin complexes with Mn(II), which would not align with the observed magnetic moment.
Therefore, the suitable ligand choice for the octahedral homoleptic Mn(II) complex with a magnetic moment of 5.9 BM is NCS-.
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