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One Integer Value Correct Type
This section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
This section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)
The number of hexagonal faces that are present is a truncated octahedron is
(2011, Integer type)
Correct answer is '8'. Can you explain this answer?
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One Integer Value Correct TypeThis section contains questions, when wo...
**Hexagonal Faces in a Truncated Octahedron**
A truncated octahedron is a polyhedron that is created by truncating the corners of an octahedron. It has a total of 14 faces, including hexagons and squares.
To determine the number of hexagonal faces in a truncated octahedron, we need to understand its structure and count the number of hexagons present.
**Structure of a Truncated Octahedron**
A truncated octahedron has 8 regular hexagons and 6 squares as its faces. The hexagons are arranged in two parallel sets of four, while the squares are located at the top and bottom of the structure.
Each hexagonal face of a truncated octahedron is connected to three other hexagons and one square. This connectivity creates a network of hexagons that form the structure of the polyhedron.
**Counting the Hexagonal Faces**
To count the number of hexagonal faces, we need to examine the connectivity of the hexagons in the truncated octahedron.
1. Start by selecting any hexagonal face in the structure.
2. From this initial hexagon, trace the edges to the neighboring hexagons.
3. Count the number of hexagons connected to the initial hexagon through its edges.
4. Repeat this process for each hexagon in the structure.
5. Keep track of the count as you move through the structure.
By following this process, you will find that each hexagon is connected to three other hexagons. Since there are 8 hexagons in a truncated octahedron, the total number of hexagonal faces is 8.
**Conclusion**
In conclusion, a truncated octahedron has 8 hexagonal faces. This is determined by examining the connectivity of the hexagons in the structure and counting the number of hexagons connected to each other.
A truncated octahedron is a polyhedron that is created by truncating the corners of an octahedron. It has a total of 14 faces, including hexagons and squares.
To determine the number of hexagonal faces in a truncated octahedron, we need to understand its structure and count the number of hexagons present.
**Structure of a Truncated Octahedron**
A truncated octahedron has 8 regular hexagons and 6 squares as its faces. The hexagons are arranged in two parallel sets of four, while the squares are located at the top and bottom of the structure.
Each hexagonal face of a truncated octahedron is connected to three other hexagons and one square. This connectivity creates a network of hexagons that form the structure of the polyhedron.
**Counting the Hexagonal Faces**
To count the number of hexagonal faces, we need to examine the connectivity of the hexagons in the truncated octahedron.
1. Start by selecting any hexagonal face in the structure.
2. From this initial hexagon, trace the edges to the neighboring hexagons.
3. Count the number of hexagons connected to the initial hexagon through its edges.
4. Repeat this process for each hexagon in the structure.
5. Keep track of the count as you move through the structure.
By following this process, you will find that each hexagon is connected to three other hexagons. Since there are 8 hexagons in a truncated octahedron, the total number of hexagonal faces is 8.
**Conclusion**
In conclusion, a truncated octahedron has 8 hexagonal faces. This is determined by examining the connectivity of the hexagons in the structure and counting the number of hexagons connected to each other.
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One Integer Value Correct TypeThis section contains questions, when wo...
please read NCERT chapter 1 class 12
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One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer?
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One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer?.
One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer?.
Solutions for One Integer Value Correct TypeThis section contains questions, when worked out will result in an integer value from 0 to 9 (both inclusive)The number of hexagonal faces that are present is a truncated octahedron is (2011, Integer type)Correct answer is '8'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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