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A 50 cm long x 20 cm diameter cylinder of brass was subjected to a tensile load of 0.1 MN. The resulting increase in length and decrease in diameter were noted 1 mm and 0.1 mm respectively. Then the brass has a Poisson’s ratio equal to
  • a)
    0.25
  • b)
    0.20
  • c)
    0.26
  • d)
    0.22
Correct answer is option 'A'. Can you explain this answer?
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Calculation of Poisson's ratio:
- Given data:
- Load (F) = 0.1 MN = 100 kN
- Original length (L) = 50 cm = 0.5 m
- Original diameter (D) = 20 cm = 0.2 m
- Increase in length (ΔL) = 1 mm = 0.001 m
- Decrease in diameter (ΔD) = 0.1 mm = 0.0001 m

Calculations:
- Strain in axial direction (ε) = ΔL / L = 0.001 / 0.5 = 0.002
- Strain in radial direction (ε') = -ΔD / D = -0.0001 / 0.2 = -0.0005
- Poisson's ratio (ν) = ε' / ε = -0.0005 / 0.002 = -0.25

Explanation:
- Poisson's ratio is a measure of the Poisson effect, which describes the behavior of a material when subjected to a load.
- In this case, the negative sign in the calculation indicates that the material contracted in the radial direction when stretched in the axial direction.
- The Poisson's ratio of brass is typically around 0.25, which is consistent with the calculated value.
- Therefore, the correct answer is option 'A' (0.25).
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A 50 cm long x 20 cm diameter cylinder of brass was subjected to a tensile load of 0.1 MN. The resulting increase in length and decrease in diameter were noted 1 mm and 0.1 mm respectively. Then the brass has a Poisson’s ratio equal toa)0.25b)0.20c)0.26d)0.22Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2025 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A 50 cm long x 20 cm diameter cylinder of brass was subjected to a tensile load of 0.1 MN. The resulting increase in length and decrease in diameter were noted 1 mm and 0.1 mm respectively. Then the brass has a Poisson’s ratio equal toa)0.25b)0.20c)0.26d)0.22Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 cm long x 20 cm diameter cylinder of brass was subjected to a tensile load of 0.1 MN. The resulting increase in length and decrease in diameter were noted 1 mm and 0.1 mm respectively. Then the brass has a Poisson’s ratio equal toa)0.25b)0.20c)0.26d)0.22Correct answer is option 'A'. Can you explain this answer?.
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