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In an exam, the average was found to be 50 marks. After deducting computational errors the marks of the 100 candidates had to be changed from 90 to 60 each and average came down to 45 marks. Total number of candidates who took the exam was:
  • a)
    150
  • b)
    200
  • c)
    300
  • d)
    600
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In an exam, the average was found to be 50 marks. After deducting comp...
Let number of candidates be n
50 × n – 100 × 30 = 45 × n
n = 600
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In an exam, the average was found to be 50 marks. After deducting comp...
Given information:
- Average score before correction = 50
- Scores of 100 candidates were changed from 90 to 60 each
- Average score after correction = 45
- We need to find the total number of candidates who took the exam

Approach:
Let's assume there were 'n' candidates who took the exam.
We can use the formula for the average:

Average = (Sum of all scores) / (Number of candidates)

We can use this formula to set up two equations and solve for 'n'.

Calculation:
1. Before correction:
- Average score = 50
- Sum of all scores = 50n
- No. of candidates = n
- Equation 1: 50 = (50n) / n

2. After correction:
- Average score = 45
- Sum of all scores = 45n
- No. of candidates = n
- Equation 2: 45 = [(90 x 100) + (60 x (n-100))] / n

We got 100 candidates who had their scores changed from 90 to 60. So, for the rest of the candidates, their scores remained the same as before.

Let's simplify equation 2:

45n = (9000 + 60(n-100)) / n
45n^2 = 9000n + 60n(n-100)
45n^2 = 9000n + 60n^2 - 6000n
15n^2 - 3000n - 9000 = 0
n^2 - 200n - 600 = 0
(n-600)(n+100) = 0

n = 600 or -100

We can discard the negative value of 'n'.
Therefore, the total number of candidates who took the exam is 600.

Answer: Option D. 600
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In an exam, the average was found to be 50 marks. After deducting comp...
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