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The number of octahedral void(s) per atom present in a cubic close-packed structure is    [CBSE AIPMT 2012]
  • a)
    2
  • b)
  • c)
    1
  • d)
    3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The number of octahedral void(s) per atom present in a cubic close-pac...
The total number of octahedral void(s) per atom present in a cubic close packed structure is 4. Besides the body centre, there is one octahedral void at the centre of each of the 12 edges. It is surrounded by six atoms, four belonging to the same unit cell (2 on the corners and 2 on face centres) and two belonging to two adjacent unit cells. Since each edge of the cube is shared between four adjacent unit cells, so is the octahedral void located on it. Only 1/4​th of each void belongs to a particular unit cell. Thus, in cubic close packed structure, octahedral void at the body-centre of the cube is 1.
12 octahedral voids located at each edge and shared between four unit cells= 
Total number of octahedral voids =4
We know that in ccp structure, each unit cell has 4 atoms. Thus, the number of octahedral voids is equal to 4/4=1.
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Most Upvoted Answer
The number of octahedral void(s) per atom present in a cubic close-pac...
ans is C
becoz there is 1 octahedral void in the centre and 1 on each edge center (which is shared by 4 atoms)
hence total no.of octahedral void =1+ 12*1/4 =4
total no. of atoms in ccp is 4
hence octahedral void per atom is 1

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Community Answer
The number of octahedral void(s) per atom present in a cubic close-pac...
Answer - (b) :-no. of atoms(n) = no. of octahedral voids (n) CCP has 4 atoms so it has 4 octahedral voids
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