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A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is
- a)− 0.5 J
- b)− 1.25 J
- c)1.25 J
- d)0.5 J
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A particle of mass 100 g is thrown vertically upwards with a speed of ...
Given data:
- Mass of the particle, m = 100 g = 0.1 kg
- Initial velocity, u = 5 m/s
Calculating work done by gravity:
- When the particle is moving upwards, the force of gravity is acting downwards in the opposite direction of motion. Therefore, the work done by gravity is negative.
- Work done by a force is given by the formula W = F*d*cosθ, where θ is the angle between the force and displacement.
- In this case, the force of gravity and displacement are in opposite directions, so θ = 180° and cosθ = -1.
- The work done by gravity is W = m*g*h, where g is the acceleration due to gravity and h is the height.
- Initial kinetic energy of the particle is K.E. = 0.5*m*u^2 = 0.5*0.1*5^2 = 1.25 J
- At the maximum height, the kinetic energy becomes zero since the particle momentarily stops.
- Therefore, the work done by gravity is equal to the initial kinetic energy of the particle, i.e., W = -1.25 J
Conclusion:
Therefore, the correct answer is option b) -1.25 J, as the work done by the force of gravity during the time the particle goes up is negative and equal to 1.25 J.
- Mass of the particle, m = 100 g = 0.1 kg
- Initial velocity, u = 5 m/s
Calculating work done by gravity:
- When the particle is moving upwards, the force of gravity is acting downwards in the opposite direction of motion. Therefore, the work done by gravity is negative.
- Work done by a force is given by the formula W = F*d*cosθ, where θ is the angle between the force and displacement.
- In this case, the force of gravity and displacement are in opposite directions, so θ = 180° and cosθ = -1.
- The work done by gravity is W = m*g*h, where g is the acceleration due to gravity and h is the height.
- Initial kinetic energy of the particle is K.E. = 0.5*m*u^2 = 0.5*0.1*5^2 = 1.25 J
- At the maximum height, the kinetic energy becomes zero since the particle momentarily stops.
- Therefore, the work done by gravity is equal to the initial kinetic energy of the particle, i.e., W = -1.25 J
Conclusion:
Therefore, the correct answer is option b) -1.25 J, as the work done by the force of gravity during the time the particle goes up is negative and equal to 1.25 J.
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A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer?.
A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up isa)− 0.5 Jb)− 1.25 Jc)1.25 Jd)0.5 JCorrect answer is option 'B'. Can you explain this answer?.
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