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A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire is
- a)2.4 N
- b)1.2 N
- c)3.0 N
- d)2.0 N
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A straight wire of length 0.5 meter and carrying a current of 1.2 ampe...
Calculation of Force on the Wire:
- The force on a current-carrying wire in a magnetic field is given by the formula:
F = I * L * B * sinθ
where:
F = force on the wire
I = current flowing through the wire (1.2 A)
L = length of the wire (0.5 m)
B = magnetic field induction (2 T)
θ = angle between the current direction and the magnetic field (90 degrees in this case)
- Substituting the values into the formula:
F = 1.2 A * 0.5 m * 2 T * sin(90°)
F = 1.2 * 0.5 * 2 * 1
F = 1.2 N
Therefore, the force on the wire is 1.2 N.
This is the correct answer which corresponds to option 'B'.
- The force on a current-carrying wire in a magnetic field is given by the formula:
F = I * L * B * sinθ
where:
F = force on the wire
I = current flowing through the wire (1.2 A)
L = length of the wire (0.5 m)
B = magnetic field induction (2 T)
θ = angle between the current direction and the magnetic field (90 degrees in this case)
- Substituting the values into the formula:
F = 1.2 A * 0.5 m * 2 T * sin(90°)
F = 1.2 * 0.5 * 2 * 1
F = 1.2 N
Therefore, the force on the wire is 1.2 N.
This is the correct answer which corresponds to option 'B'.
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A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?
Question Description
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?.
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?.
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