JEE Exam > JEE Questions > A straight wire of length 0.5 meter and carry...
Start Learning for Free
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire is
- a)2.4 N
- b)1.2 N
- c)3.0 N
- d)2.0 N
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A straight wire of length 0.5 meter and carrying a current of 1.2 ampe...
Calculation of Force on the Wire:
- The force on a current-carrying wire in a magnetic field is given by the formula:
F = I * L * B * sinθ
where:
F = force on the wire
I = current flowing through the wire (1.2 A)
L = length of the wire (0.5 m)
B = magnetic field induction (2 T)
θ = angle between the current direction and the magnetic field (90 degrees in this case)
- Substituting the values into the formula:
F = 1.2 A * 0.5 m * 2 T * sin(90°)
F = 1.2 * 0.5 * 2 * 1
F = 1.2 N
Therefore, the force on the wire is 1.2 N.
This is the correct answer which corresponds to option 'B'.
- The force on a current-carrying wire in a magnetic field is given by the formula:
F = I * L * B * sinθ
where:
F = force on the wire
I = current flowing through the wire (1.2 A)
L = length of the wire (0.5 m)
B = magnetic field induction (2 T)
θ = angle between the current direction and the magnetic field (90 degrees in this case)
- Substituting the values into the formula:
F = 1.2 A * 0.5 m * 2 T * sin(90°)
F = 1.2 * 0.5 * 2 * 1
F = 1.2 N
Therefore, the force on the wire is 1.2 N.
This is the correct answer which corresponds to option 'B'.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?
Question Description
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?.
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A straight wire of length 0.5 meter and carrying a current of 1.2 ampere is placed in a uniform magnetic field of induction 2 telsa. The magnetic field is perpendicular to the length of the wire. The force on the wire isa)2.4 Nb)1.2 Nc)3.0 Nd)2.0 NCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup