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Two wires of equal length are placed perpendicular to the plane of paper at a distance of 5 cm from each other. If the currents flowing in first and second wires are 2 A and 5 A respectively in opposite direction, then the resultant magnetic field at mid-point of both the wires is
  • a)
    2.8 μ₀/2π
  • b)
    μ₀/2.8π
  • c)
    μ₀/2π
  • d)
    μ₀/π
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two wires of equal length are placed perpendicular to the plane of pap...
Understanding the Problem:
Given:
- Two wires of equal length placed perpendicular to the plane of paper
- The wires are at a distance of 5 cm from each other
- Current in the first wire = 2 A
- Current in the second wire = 5 A in the opposite direction

Calculating the Magnetic Field:
- The magnetic field due to a current-carrying wire is given by the formula: B = μ0I / 2πr
- At the midpoint of the wires, the magnetic field due to the first wire is B1 = μ0(2) / 2π(2.5) = μ0 / 2π
- The magnetic field due to the second wire is B2 = μ0(5) / 2π(2.5) = 2μ0 / 2π
- Since the currents in the wires are in opposite directions, the net magnetic field at the midpoint is the difference between the two fields: B = B2 - B1 = 2μ0 / 2π - μ0 / 2π = μ0 / 2π
Therefore, the resultant magnetic field at the midpoint of both the wires is μ0 / 2π, which corresponds to option 'A'.
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Two wires of equal length are placed perpendicular to the plane of paper at a distance of 5 cm from each other. If the currents flowing in first and second wires are 2 A and 5 A respectively in opposite direction, then the resultant magnetic field at mid-point of both the wires isa)2.8 μ/2πb)μ/2.8πc)μ/2πd)μ/πCorrect answer is option 'A'. Can you explain this answer?
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