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12 men can dig 8 meters long trench in a day. How many men should be employed for digging 50 meter long trench of the same type in one day?

  • a)
    75

  • b)
    50

  • c)
    25

  • d)
    None of these

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
12 men can dig 8 meters long trench in a day. How many men should be e...
Let's solve the problem using the concept of direct proportion.
Given:
  • 12 men can dig an 8-meter-long trench in one day.
  • We need to find the number of men required to dig a 50-meter-long trench in one day.
Step 1: Establish the proportion
The number of men required is directly proportional to the length of the trench.
Let x be the number of men required to dig the 50-meter trench.
Men∝Length of trench
 
So,
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Most Upvoted Answer
12 men can dig 8 meters long trench in a day. How many men should be e...
B-75
as it is direct variation
MEN. DISTANCE
12. 8m
?(x). 50

12:x::8:50(product of means=product of extremes)
12×50=x×8
12×50\8=x
=75men
Free Test
Community Answer
12 men can dig 8 meters long trench in a day. How many men should be e...
To find out how many men should be employed for digging a 50-meter long trench in one day, we can use the concept of ratios and proportions.

Given:
- 12 men can dig an 8-meter long trench in a day.

Let's assume that x men can dig a 50-meter long trench in one day.

Using the concept of proportions, we can set up the following equation:

12 men / 8 meters = x men / 50 meters

Cross multiplying the equation, we get:

12 men * 50 meters = 8 meters * x men

Simplifying further, we have:

600 men-meters = 8x men-meters

Dividing both sides of the equation by 8, we get:

600 / 8 = x

x = 75

Therefore, 75 men should be employed for digging a 50-meter long trench in one day.

So, the correct answer is option A) 75 men.
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12 men can dig 8 meters long trench in a day. How many men should be employed for digging 50 meter long trench of the same type in one day?a)75b)50c)25d)None of theseCorrect answer is option 'A'. Can you explain this answer?
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