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Virtual image is always
- a)Inverted and diminished
- b)Erect and magnified or diminished
- c)Inverted and magnified
- d)Erect and magnified
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Virtual image is alwaysa)Inverted and diminishedb)Erect and magnified ...
Virtual image is always erect and magnified or diminished and behind the mirror.
Most Upvoted Answer
Virtual image is alwaysa)Inverted and diminishedb)Erect and magnified ...
Explanation:
When we talk about a virtual image, it is an image that appears to be formed where the light rays do not actually meet. The light rays only appear to meet at a point, but they do not actually converge at that point. Therefore, the virtual image is always formed behind the mirror or lens as the light does not actually converge at that point.
Characteristics of Virtual Image:
Therefore, the correct answer is option B, which states that a virtual image is always erect and magnified or diminished.
When we talk about a virtual image, it is an image that appears to be formed where the light rays do not actually meet. The light rays only appear to meet at a point, but they do not actually converge at that point. Therefore, the virtual image is always formed behind the mirror or lens as the light does not actually converge at that point.
Characteristics of Virtual Image:
- It is always erect, which means it is not upside down.
- It can be magnified or diminished, but only in size, not in orientation.
- It cannot be projected onto a screen as it is not a real image.
- The distance of the virtual image from the mirror or lens is negative, indicating that it is always behind the mirror or lens.
- The size of the virtual image depends on the distance of the object from the mirror or lens, and the focal length of the mirror or lens.
Therefore, the correct answer is option B, which states that a virtual image is always erect and magnified or diminished.
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Virtual image is alwaysa)Inverted and diminishedb)Erect and magnified or diminishedc)Inverted and magnifiedd)Erect and magnifiedCorrect answer is option 'B'. Can you explain this answer?
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