The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6isa)0b)2.84c)4.90d)5.92Correct answer is option 'A'. Can you explain this answer?

Question

Answer

The electron configuration is [Ar]3d^5 4s^1.We have to accomodate the 6 Ligands and the fact that CO is a strong ligand.

This results in d^2sp^3 hybridization. Therefore, there are no unpaired electrons in Cr(CO)6. Hence n=0

And the spin only magnetic moment is also 0.

Answer

Since CO is a strong ligand so there is no unpaired electron in Cr so the spin magnetic moment is equal to zero...

Answer

Please answer this question

Answer

CO is Strong ligand .So,CO in magnetic moment is Zero. Hence Option (a) is Correct.

Answer

The spin-only magnetic moment value of Cr(CO)6 is 0. This can be explained by considering the electronic configuration of Cr(CO)6 and applying the spin-only formula.

Cr(CO)6 consists of a central chromium atom bonded to six carbon monoxide (CO) ligands. The atomic number of chromium is 24, and its electronic configuration is [Ar] 3d5 4s1.

To determine the spin-only magnetic moment, we need to consider the number of unpaired electrons in the d-orbital of the central chromium atom. According to Hund's rule, electrons occupy separate orbitals with parallel spins before pairing up. Therefore, we need to determine the number of unpaired electrons in the d-orbital.

The d-orbital of chromium can accommodate a maximum of 10 electrons. Since the electronic configuration of chromium is 3d5, there are 5 electrons in the d-orbital. Therefore, there are 5 unpaired electrons.

The spin-only magnetic moment (μ) can be calculated using the formula:

μ = √(n(n+2)) BM

where n is the number of unpaired electrons and BM is the Bohr magneton unit (μB).

In this case, n = 5. Substituting the values into the formula:

μ = √(5(5+2)) BM
= √(5*7) BM
= √35 BM

The value of √35 is approximately 5.92. Therefore, the spin-only magnetic moment of Cr(CO)6 is approximately 5.92 Bohr magneton units.

However, the correct answer given is option 'A', which states that the spin-only magnetic moment value is 0. This suggests that there are no unpaired electrons in the d-orbital of the central chromium atom.

One possible explanation for this discrepancy is that the ligands, carbon monoxide (CO), can participate in π-bonding with the central chromium atom, resulting in paired electrons in the d-orbital and no unpaired electrons. This would lead to a spin-only magnetic moment value of 0.

It is important to note that the spin-only magnetic moment is an approximation based on the assumption that the compound has a high-spin configuration and that there is no orbital contribution to the magnetic moment. In reality, the presence of ligands can affect the electronic structure and magnetic properties of the compound.

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