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For the redox reaction :
Zn (s) + Cu2+ (0.1M) → Zn2+ (1M) + Cu(s) taking place in a cell, Eºcell is 1.10 volt. Ecell for the cell will be
   [AIEEE-2003]
  • a)
    1.07 volt
  • b)
    0.82 volt
  • c)
    2.14 volt
  • d)
    1.8 volt
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
For the redox reaction :Zn (s) + Cu2+(0.1M) →Zn2+(1M) + Cu(s) tak...
The correct answer is Option A.
Eocell =  Ecell – (0.0591/n) log (Zn2+/ Cu2+)
= 1.10 – (0.0591/n) log (1 / 0.1)
= 1.10 – 0.02955
= 1.070 Volt
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For the redox reaction :Zn (s) + Cu2+(0.1M) →Zn2+(1M) + Cu(s) tak...
yaa it is correct ans Ecell=Eocell -0.0591/n logzn2+/Cu2+ =1.10-0.0591/2 log 1M/0.1M =1.10-0.0295 log10 =1.0705 =1.07V
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For the redox reaction :Zn (s) + Cu2+(0.1M) →Zn2+(1M) + Cu(s) taking place in a cell, Eºcellis 1.10 volt. Ecellfor the cell will be [AIEEE-2003]a)1.07 voltb)0.82 voltc)2.14 voltd)1.8 voltCorrect answer is option 'A'. Can you explain this answer?
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