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Find the sum of the first 5 terms of the AP: 10, 6, 2…
  • a)
    –320
  • b)
    512
  • c)
    10
  • d)
    –960
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Find the sum of the first 5 terms of the AP: 10, 6, 2…a)–...
AP: 10, 6, 2, …
a = 10, d = - 4
Sum of first n terms = S(n) = (n/2) x [2a + (n – 1) x d]
S5 = (5/2) x [2 x (10) + (5 – 1) x (-4)]
= (5/2) x [20 + 4 x (-4)]
= (5/2) x (20 – 16)
= (5/2) x (4)
= 5 x 2
= 10
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Most Upvoted Answer
Find the sum of the first 5 terms of the AP: 10, 6, 2…a)–...
Sum of the first 5 terms of an AP
To find the sum of the first 5 terms of an Arithmetic Progression (AP), you can use the formula:
\[ S_n = \frac{n}{2} \times [2a + (n-1)d] \]
where:
- \(S_n\) is the sum of the first \(n\) terms
- \(n\) is the number of terms
- \(a\) is the first term of the AP
- \(d\) is the common difference between consecutive terms

Given AP
The given AP is: 10, 6, 2, ...
From the given AP, you can identify:
- First term, \(a = 10\)
- Common difference, \(d = 6 - 10 = -4\)
- Number of terms, \(n = 5\)

Calculating the sum
Substitute the values into the formula:
\[ S_5 = \frac{5}{2} \times [2 \times 10 + (5-1) \times (-4)] \]
\[ S_5 = \frac{5}{2} \times [20 + 4 \times (-4)] \]
\[ S_5 = \frac{5}{2} \times [20 - 16] \]
\[ S_5 = \frac{5}{2} \times 4 \]
\[ S_5 = 10 \]
Therefore, the sum of the first 5 terms of the given AP is 10. This matches with option 'C'.
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