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A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N in the horizontal direction is applied at the mid-point of the rope, as shown. What is the angle the rope makes with the vertical in equilibrium?
  • a)
    60o
  • b)
    40o
  • c)
    50o
  • d)
    30o
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A ...
Making the free body diagram of the body we get
T1.cosθ = T2 = mg = 60
T1.sinθ = 50N
By dividing the above two equations we get
tanθ = 5/6
Thus we get θ = 40°
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A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A ...
Here as they all are in equilibrium by resolving into components. ( here I have assumed that the angle is A instead between string and normal) .....T1cosA = 60NT1sinA = 50N.....
by dividing we get tanA = 5/6. so by taking inverse we get A= 40
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