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The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:
- a)Four unpaired electrons
- b)Three unpaired electrons
- c)Two unpaired electrons
- d)Zero unpaired electrons
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Fou...
Magnetic Moment of [Ru(H2O)6]2+
Magnetic moment is the measure of the strength of a magnetic field created by a substance. It is a property of all materials, including atoms, ions, and molecules.
[Ru(H2O)6]2+ is a complex ion that contains ruthenium ion (Ru2+) and six water molecules (H2O). The magnetic moment of this complex ion can be calculated using the formula:
μ = √n(n+2)BM
where μ is the magnetic moment, n is the number of unpaired electrons and BM is the Bohr magneton (9.27 x 10^-24 J/T).
Calculation of Magnetic Moment
To determine the magnetic moment of [Ru(H2O)6]2+, we need to first find the number of unpaired electrons in the ruthenium ion.
Ruthenium ion has the electron configuration [Kr]4d^7. According to Hund's rule, the seven electrons in the d subshell will occupy separate orbitals with parallel spins before pairing up. Therefore, the ruthenium ion has five unpaired electrons.
Using the formula, we get:
μ = √5(5+2)BM
μ = √35BM
μ = 5.92 BM
The magnetic moment of [Ru(H2O)6]2+ is 5.92 BM, which corresponds to zero unpaired electrons. This means that all the electrons in the ruthenium ion are paired up.
Conclusion
The magnetic moment of [Ru(H2O)6]2+ is 5.92 BM, which corresponds to zero unpaired electrons. Therefore, the correct answer is option D.
Magnetic moment is the measure of the strength of a magnetic field created by a substance. It is a property of all materials, including atoms, ions, and molecules.
[Ru(H2O)6]2+ is a complex ion that contains ruthenium ion (Ru2+) and six water molecules (H2O). The magnetic moment of this complex ion can be calculated using the formula:
μ = √n(n+2)BM
where μ is the magnetic moment, n is the number of unpaired electrons and BM is the Bohr magneton (9.27 x 10^-24 J/T).
Calculation of Magnetic Moment
To determine the magnetic moment of [Ru(H2O)6]2+, we need to first find the number of unpaired electrons in the ruthenium ion.
Ruthenium ion has the electron configuration [Kr]4d^7. According to Hund's rule, the seven electrons in the d subshell will occupy separate orbitals with parallel spins before pairing up. Therefore, the ruthenium ion has five unpaired electrons.
Using the formula, we get:
μ = √5(5+2)BM
μ = √35BM
μ = 5.92 BM
The magnetic moment of [Ru(H2O)6]2+ is 5.92 BM, which corresponds to zero unpaired electrons. This means that all the electrons in the ruthenium ion are paired up.
Conclusion
The magnetic moment of [Ru(H2O)6]2+ is 5.92 BM, which corresponds to zero unpaired electrons. Therefore, the correct answer is option D.
Community Answer
The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Fou...
Ru is element of 4d series with atomic no 44..and all 4d and 5d series due to their big size they rearrangement the electron and form inner orbital complex..thats why magnetic monent is zero in this case
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The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer?
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The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer?.
The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnetic moment [Ru (H2O)6]2+ corresponds to the presence of:a)Four unpaired electronsb)Three unpaired electronsc)Two unpaired electronsd)Zero unpaired electronsCorrect answer is option 'D'. Can you explain this answer?.
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