In the electronic structure of H2SO4, the total number of unshared ele...
Explanation:
The electronic structure of H2SO4 can be determined by considering the valence electrons of each atom in the molecule.
Valence Electrons:
Sulfur (S) has 6 valence electrons (in the third shell), while Oxygen (O) has 6 valence electrons (in the second shell), and Hydrogen (H) has 1 valence electron (in the first shell).
Covalent Bonding:
In H2SO4, each hydrogen atom shares its single valence electron with one of the oxygen atoms to form a covalent bond. Similarly, each oxygen atom shares two of its valence electrons with the sulfur atom to form two covalent bonds.
Shared Electrons:
Therefore, the total number of electrons shared in the covalent bonds in H2SO4 is:
2(H-H) + 2(O-S) + 4(O-H) = 2(2) + 2(2) + 4(2) = 16
Unshared Electrons:
In addition to the shared electrons, there are also unshared electrons present in the molecule. Each oxygen atom has two unshared pairs of valence electrons, for a total of 4 unshared pairs.
Total Unshared Electrons:
Therefore, the total number of unshared electrons in H2SO4 is:
4(O) = 4(2) = 8
Adding the number of shared and unshared electrons gives:
16 (shared electrons) + 8 (unshared electrons) = 24 (total electrons)
Therefore, the correct answer is 16.
In the electronic structure of H2SO4, the total number of unshared ele...
By drawing a proper Lewis structure u will get answer ...the question is asking for electron ..not for lone pair ...