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An ideal transformer has 500 and 5000 turns in primary and secondary windings respectively. If the primary voltage is connected to a 6V battery then the secondary voltage is
  • a)
    0
  • b)
    60 V
  • c)
    0.6 V
  • d)
    6.0 V
Correct answer is option 'A'. Can you explain this answer?
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An ideal transformer has 500 and 5000 turns in primary and secondary w...
Calculation:
The voltage ratio in an ideal transformer is equal to the turns ratio. Therefore, the secondary voltage can be calculated using the formula:
\[
\frac{V_p}{V_s} = \frac{N_p}{N_s}
\]
Where:
- \(V_p\) is the primary voltage (6 V)
- \(V_s\) is the secondary voltage
- \(N_p\) is the number of turns in the primary winding (500 turns)
- \(N_s\) is the number of turns in the secondary winding (5000 turns)

Calculation:
Substitute the given values into the formula:
\[
\frac{6}{V_s} = \frac{500}{5000}
\]
\[
V_s = \frac{5000}{500} \times 6
\]
\[
V_s = 0 \text{ V}
\]
Therefore, the secondary voltage is 0 V. This implies that no voltage is induced across the secondary winding when the primary voltage is connected to a 6V battery.
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An ideal transformer has 500 and 5000 turns in primary and secondary windings respectively. If the primary voltage is connected to a 6V battery then the secondary voltage isa)0b)60 Vc)0.6 Vd)6.0 VCorrect answer is option 'A'. Can you explain this answer?
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