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Number of atoms present in 52 g of helium is:
(NA is Avogadro’s constant Gram atomic mass of He is 4 g)​
  • a)
    26 X NA
  • b)
    NA
  • c)
    13 X NA
  • d)
    52 Χ NA
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Number of atoms present in 52 g of helium is:(NAis Avogadro’s co...
Gram atomic mass of helium is 4 g so number of atoms present in 52 g of helium= 52/4 X NA = 13 NA 
Community Answer
Number of atoms present in 52 g of helium is:(NAis Avogadro’s co...
Calculation of Number of Atoms in 52 g of Helium

Given:
Mass of helium (m) = 52 g
Gram atomic mass of helium (M) = 4 g

We know that the number of atoms present in a sample can be calculated by using the following formula:

Number of atoms = (mass of sample / gram atomic mass) x Avogadro's number

where Avogadro's number (NA) is a constant with a value of 6.022 x 10^23 atoms/mol.

Using the above formula, we can calculate the number of atoms present in 52 g of helium as follows:

Number of atoms = (52 g / 4 g) x 6.022 x 10^23 atoms/mol
Number of atoms = 13 x 6.022 x 10^23 atoms
Number of atoms = 7.83 x 10^24 atoms

Therefore, the correct answer is option C, which states that there are 13 times Avogadro's number of atoms present in 52 g of helium.
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Number of atoms present in 52 g of helium is:(NAis Avogadro’s constantGram atomic mass of He is 4 g)​a)26 X NAb)NAc)13 X NAd)52 Χ NACorrect answer is option 'C'. Can you explain this answer?
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