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If cosθ+cos7θ+cos3θ+cos5θ=0, then θ=
  • a)
    nπ/4
  • b)
    nπ/2
  • c)
    nπ/8
  • d)
    nπ/6
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
If cosθ+cos7θ+cos3θ+cos5θ=0, then θ=a)n&...
Given Equation:
cosθ + cos7θ + cos3θ + cos5θ = 0

Solution:

Using the Sum to Product Formula:
We know that cosA + cosB = 2cos((A+B)/2)cos((A-B)/2)
Therefore, we can rewrite the given equation as:
2cos4θcos3θ + 2cos4θcosθ = 0
2cos4θ(cos3θ + cosθ) = 0

Using the Given Equation:
Since the given equation is cosθ + cos7θ + cos3θ + cos5θ = 0, we can rearrange the terms to get:
cosθ + cos3θ + cos5θ + cos7θ = 0
(cosθ + cos7θ) + (cos3θ + cos5θ) = 0
2cos4θ(cos3θ + cosθ) = 0

Conclusion:
Comparing the two expressions we derived, we find that:
2cos4θ(cos3θ + cosθ) = 2cos4θ(cos3θ + cosθ) = 0
This implies that either cos4θ = 0 or cos3θ + cosθ = 0

Final Step:
Since cos4θ = 0 implies θ = nπ/2, and cos3θ + cosθ = 0 implies θ = nπ/8, the correct answer is θ = nπ/8. Therefore, option C is the correct choice.
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If cosθ+cos7θ+cos3θ+cos5θ=0, then θ=a)nπ/4b)nπ/2c)nπ/8d)nπ/6Correct answer is option 'C'. Can you explain this answer?
Question Description
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