JEE Exam  >  JEE Questions  >  If tan^-1 (sin^2 theta 2sin theta 2) cot^... Start Learning for Free
If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1?
Most Upvoted Answer
If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 ha...
To solve the given equation, let's simplify it step by step:

Step 1: Simplify the expression inside the first inverse tangent (tan^-1).

tan^-1 (sin^2θ + 2sinθ + 2)

Step 2: Use the trigonometric identity sin^2θ + cos^2θ = 1.

sin^2θ + 2sinθ + 2 = 1 - cos^2θ + 2sinθ + 2

Step 3: Rearrange the terms.

cos^2θ - 2sinθ + 1 = 0

Step 4: Factorize the quadratic equation.

(cosθ - 1)(cosθ + 1) - 2sinθ = 0

Step 5: Simplify.

(cosθ - 1)(cosθ + 1) = 2sinθ

Step 6: Divide both sides by cosθ.

cosθ + 1 = 2sinθ / cosθ

Step 7: Use the trigonometric identity tanθ = sinθ / cosθ.

cosθ + 1 = 2tanθ

Step 8: Simplify.

2tanθ - cosθ - 1 = 0

Now, let's simplify the expression inside the second inverse cotangent (cot^-1).

cot^-1 (4sec^2φ + 1)

Step 1: Use the trigonometric identity sec^2φ = 1 + tan^2φ.

4(1 + tan^2φ) + 1

Step 2: Simplify.

4 + 4tan^2φ + 1

Step 3: Combine like terms.

5 + 4tan^2φ

Step 4: Use the trigonometric identity tan^2φ = sec^2φ - 1.

5 + 4(sec^2φ - 1)

Step 5: Simplify.

4sec^2φ + 1

Now, let's substitute the simplified expressions back into the original equation:

2tanθ - cosθ - 1 = cot^-1 (4sec^2φ + 1)

Since the equation is equal to π/2, we can rewrite it as:

2tanθ - cosθ - 1 = π/2

Now, let's analyze the options and determine which one(s) satisfy the equation:

A) sinθ = -1
If sinθ = -1, then tanθ = sinθ / cosθ = -1 / cosθ.
Substituting into the equation:
2(-1 / cosθ) - cosθ - 1 = π/2
This equation does not hold true for all values of cosθ, so option A is not a valid solution.

B) sinφ = 1
If sinφ = 1, then cosφ = √(1 - sin^2φ) = √(1 - 1) = 0.
Substituting into the equation:
2tanθ - cosθ - 1 = π/2
This equation does not hold true for all values of tanθ, so option B is not a valid solution.

C) cosθ = 1
If cosθ = 1, then tanθ = sinθ / cosθ = sinθ.
Substituting into the equation:
2sinθ - 1 -
Explore Courses for JEE exam
If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1?
Question Description
If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1?.
Solutions for If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? defined & explained in the simplest way possible. Besides giving the explanation of If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1?, a detailed solution for If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? has been provided alongside types of If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? theory, EduRev gives you an ample number of questions to practice If tan^-1 (sin^2 theta 2sin theta 2) cot^-1(4sec^2 phi 1)=pi/2 has solution for some theta and phi then A) sin theta = - 1 B) sin phi = 1 C) cos theta = 1 D) cos pho = - 1? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev