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Given that θ is a acute and that sin θ =3/5. Let x,y be positive real numbers such that 3(x-y) =1, then one set of solutions for x and y expressed in terms of θ is given by
  • a)
    x=sec θ,y=cosec θ
  • b)
    x=x=cot θ,y= tan θ
  • c)
    x=cosce θ,y=cot θ
  • d)
    x=sec θ,y= tan θ
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Given that θ is a acute and that sin θ =3/5. Let x,y be po...
There seems to be some information missing from the beginning of this sentence. Could you please provide more context so that I can assist you better?
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Given that θ is a acute and that sin θ =3/5. Let x,y be po...
Theta is acute so in the 1st quadrant. x,y>0
sin is 3/5 , tan will be 3/4
cosec will be 5/3 & cot will be 4/3
cosec-cot = 1/3 = x-y (as in question)
now compare x & y.
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Given that θ is a acute and that sin θ =3/5. Let x,y be positive real numbers such that 3(x-y) =1, then one set of solutions for x and y expressed in terms of θ is given bya)x=sec θ,y=cosec θb)x=x=cot θ,y= tan θc)x=cosce θ,y=cot θd)x=sec θ,y= tan θCorrect answer is option 'C'. Can you explain this answer?
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Given that θ is a acute and that sin θ =3/5. Let x,y be positive real numbers such that 3(x-y) =1, then one set of solutions for x and y expressed in terms of θ is given bya)x=sec θ,y=cosec θb)x=x=cot θ,y= tan θc)x=cosce θ,y=cot θd)x=sec θ,y= tan θCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Given that θ is a acute and that sin θ =3/5. Let x,y be positive real numbers such that 3(x-y) =1, then one set of solutions for x and y expressed in terms of θ is given bya)x=sec θ,y=cosec θb)x=x=cot θ,y= tan θc)x=cosce θ,y=cot θd)x=sec θ,y= tan θCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given that θ is a acute and that sin θ =3/5. Let x,y be positive real numbers such that 3(x-y) =1, then one set of solutions for x and y expressed in terms of θ is given bya)x=sec θ,y=cosec θb)x=x=cot θ,y= tan θc)x=cosce θ,y=cot θd)x=sec θ,y= tan θCorrect answer is option 'C'. Can you explain this answer?.
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