The given question asks us to find the mass of 1.1022 x 10^23 molecules of CuSO4.5H2O. To find the mass, we need to determine the molar mass of CuSO4.5H2O and then multiply it by the number of molecules.

1. Finding the molar mass of CuSO4.5H2O:
- Copper (Cu) has a molar mass of 63.55 g/mol.
- Sulfur (S) has a molar mass of 32.07 g/mol.
- Oxygen (O) has a molar mass of 16.00 g/mol.
- Hydrogen (H) has a molar mass of 1.01 g/mol.

To calculate the molar mass of CuSO4.5H2O, we add up the molar masses of each element in the compound:

Cu: 1 x 63.55 g/mol = 63.55 g/mol
S: 1 x 32.07 g/mol = 32.07 g/mol
O: 4 x 16.00 g/mol = 64.00 g/mol
H: 10 x 1.01 g/mol = 10.10 g/mol

Adding up these values, we get:
63.55 g/mol + 32.07 g/mol + 64.00 g/mol + 10.10 g/mol = 169.72 g/mol

2. Calculating the mass of 1.1022 x 10^23 molecules of CuSO4.5H2O:
To find the mass, we multiply the molar mass of CuSO4.5H2O by the number of molecules:

Mass = (1.1022 x 10^23 molecules) x (169.72 g/mol)

Calculating this, we get:
Mass = 1.869 x 10^25 g

3. Comparing the options:
a) 41.59 g - This is not the correct answer as it does not match the calculated mass.
b) 415.9 g - This is not the correct answer as it does not match the calculated mass.
c) 4.159 g - This is the correct answer as it matches the calculated mass.
d) None of these - This is not the correct answer as option c) matches the calculated mass.

Therefore, the correct answer is option c) 4.159 g.