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Light of wavelength 5000Å falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will be
  • a)
    0.58 eV
  • b)
    2.48 eV
  • c)
    1.24 eV
  • d)
    1.16 eV
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Light of wavelength 5000 falls on a sensitive plate with photoelectric...
Given data:
Wavelength of light (λ) = 5000 Å = 5000 x 10^-10 m
Work function (φ) = 1.9 eV

Calculating energy of incident photon:
Energy of a photon is given by E = hc/λ, where h is the Planck's constant (6.63 x 10^-34 J s) and c is the speed of light (3 x 10^8 m/s).
Substitute the given values to find E.

Calculating kinetic energy of the photoelectron:
The kinetic energy (K.E.) of the photoelectron is given by K.E. = E - φ, where E is the energy of the incident photon and φ is the work function.
Substitute the values of E and φ to find the kinetic energy of the photoelectron.

Calculation:
Energy of incident photon (E) = 6.63 x 10^-34 J s x 3 x 10^8 m/s / (5000 x 10^-10 m) = 3.98 x 10^-19 J = 2.48 eV
Kinetic energy of the photoelectron = 2.48 eV - 1.9 eV = 0.58 eV
Therefore, the correct answer is option 'A' which is 0.58 eV.
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Light of wavelength 5000 falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will bea)0.58 eVb)2.48 eVc)1.24 eVd)1.16 eVCorrect answer is option 'A'. Can you explain this answer?
Question Description
Light of wavelength 5000 falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will bea)0.58 eVb)2.48 eVc)1.24 eVd)1.16 eVCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Light of wavelength 5000 falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will bea)0.58 eVb)2.48 eVc)1.24 eVd)1.16 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light of wavelength 5000 falls on a sensitive plate with photoelectric work function of 1.9 eV. The kinetic energy of the photoelectron emitted will bea)0.58 eVb)2.48 eVc)1.24 eVd)1.16 eVCorrect answer is option 'A'. Can you explain this answer?.
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