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A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer?.

Solutions for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A 10 μF capacitor is charged to a potential difference 50 V and it is then connected to another uncharged capacitor in parallel. If common potential difference becomes 20 V, then capacitance of the second capacitor isa)10 μFb)15 μFc)20 μFd)30 μFCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.