The number 35a246772 is in base 9. This number when written in base 10...
(35a246772)9
= (3 x 98) + (5 x 97) + (a x 96) + ... + (2 x 90)
= [3 x (8 + 1)8] + [5 x (8 + 1)7] + [a x (8 + 1)6] + ... + [2 x (8 + 1)6]
When the above expression is expanded, only the last term of each binomial expression is not divisible by 8.
Thus, the number will be divisible when sum of its digits is divisible by 8. Sum of digits = 3 + 5 + <z + 2 + 4 + 6 + 7 + 7 + 2 = 36 + a The sum will be divisible by 8 when a = 4.
Answer: 4
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The number 35a246772 is in base 9. This number when written in base 10...
Given:
The number 35a246772 is in base 9.
The number when written in base 10 is divisible by 8.
We need to find the value of digit a.
Approach:
To find the value of digit a, we need to convert the number from base 9 to base 10 and check if it is divisible by 8.
The conversion from base 9 to base 10 can be done by multiplying each digit of the number with the corresponding power of 9 and summing them up.
If the resulting number is divisible by 8, then the value of digit a will satisfy the given condition.
Conversion from Base 9 to Base 10:
To convert the number 35a246772 from base 9 to base 10, we can use the following formula:
Number in base 10 = (3 * 9^9) + (5 * 9^8) + (a * 9^7) + (2 * 9^6) + (4 * 9^5) + (6 * 9^4) + (7 * 9^3) + (7 * 9^2) + (2 * 9^1)
Simplifying this expression gives:
Number in base 10 = 387420489 + 2952450a + 78732 + 13122 + 26244 + 4374 + 567 + 81 + 18
Number in base 10 = 387426705 + 2952450a
Checking Divisibility by 8:
To check if the number in base 10 is divisible by 8, we need to divide it by 8 and see if the remainder is 0.
Let's divide the number by 8:
387426705 + 2952450a = 8 * 48428338 + 2952450a
The remainder is 2952450a.
Since the given number is divisible by 8, the remainder should be 0.
Thus, we have the equation 2952450a = 0.
The only value of a that satisfies this equation is a = 0.
Conclusion:
The value of digit a in the number 35a246772, when written in base 9, is 0.
The number 35a246772 is in base 9. This number when written in base 10...
Check the last term of every term in which every digit is multiplied to 1^8 =1, 1^7=1 and so on, so digits are getting added, while rest are divisible by 8 because they are multiplying 8 and being added so they will be divisible, now when they are added, all digits of number will add 3+5+a+2 and so on... Hence, if it is divisible 8, so should be the sum!
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