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The radius of air bubble is increasing at the rate of 0. 25 cm/s. At what rate the volume of the bubble is increasing when the radius is 1 cm.​
  • a)
    4π cm3/s
  • b)
    22π cm3/s
  • c)
    2π cm3/s
  • d)
    π cm3/s
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The radius of air bubble is increasing at the rate of 0. 25 cm/s. At w...
Given, the rate of increase of radius of the air bubble = 0.25 cm/s

We need to find the rate of increase of volume of the bubble when the radius is 1 cm.

Formula used:

Volume of a sphere = (4/3)πr^3

Differentiating both sides with respect to time t, we get:

dV/dt = 4πr^2(dr/dt)

where dV/dt is the rate of change of volume of the sphere with respect to time t and dr/dt is the rate of change of radius of the sphere with respect to time t.

Substituting the given values, we get:

dV/dt = 4π(1)^2(0.25) = π cm^3/s

Therefore, the rate of increase of volume of the bubble when the radius is 1 cm is π cm^3/s, which is the correct answer.
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The radius of air bubble is increasing at the rate of 0. 25 cm/s. At w...
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The radius of air bubble is increasing at the rate of 0. 25 cm/s. At what rate the volume of the bubble is increasing when the radius is 1 cm.​a)4π cm3/sb)22π cm3/sc)2π cm3/sd)π cm3/sCorrect answer is option 'D'. Can you explain this answer?
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