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Consider f (x) = x2 /| x | , x ≠ 0, f(x) = 0, x = 0
  • a)
    f(x) is discontinuous everywhere
  • b)
    f(x) is continuous everywhere
  • c)
    f ′ (x) exists in − 1,1
  • d)
    f ′ (x) exists in − 2,2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider f (x)= x2/| x | , x ≠ 0, f(x)= 0, x = 0a)f(x) is discontin...
Explanation:

Continuity of f(x):
- The function f(x) is defined as f(x) = x^2 / |x| for x ≠ 0 and f(x) = 0 for x = 0.
- For x ≠ 0, f(x) = x^2 / |x| = x. As x approaches 0 from the left, f(x) approaches 0. Similarly, as x approaches 0 from the right, f(x) approaches 0.
- Therefore, the limit of f(x) as x approaches 0 exists and is equal to 0, which is also the value of f(x) at x = 0.
- Hence, f(x) is continuous at x = 0.

Continuity Everywhere:
- For x ≠ 0, f(x) = x^2 / |x| = x, which is a continuous function everywhere except at x = 0.
- At x = 0, f(x) is defined separately as 0, which is also a continuous function at x = 0.
- Therefore, f(x) is continuous everywhere.

Conclusion:
- The correct answer is option 'B' which states that f(x) is continuous everywhere.
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Consider f (x)= x2/| x | , x ≠ 0, f(x)= 0, x = 0a)f(x) is discontinuous everywhereb)f(x) is continuous everywherec)f ′ (x)exists in − 1,1d)f ′ (x)exists in − 2,2Correct answer is option 'B'. Can you explain this answer?
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Consider f (x)= x2/| x | , x ≠ 0, f(x)= 0, x = 0a)f(x) is discontinuous everywhereb)f(x) is continuous everywherec)f ′ (x)exists in − 1,1d)f ′ (x)exists in − 2,2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider f (x)= x2/| x | , x ≠ 0, f(x)= 0, x = 0a)f(x) is discontinuous everywhereb)f(x) is continuous everywherec)f ′ (x)exists in − 1,1d)f ′ (x)exists in − 2,2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider f (x)= x2/| x | , x ≠ 0, f(x)= 0, x = 0a)f(x) is discontinuous everywhereb)f(x) is continuous everywherec)f ′ (x)exists in − 1,1d)f ′ (x)exists in − 2,2Correct answer is option 'B'. Can you explain this answer?.
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