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Among the following, the unstable carbonyl species is:
- a)Mn(CO)5Cl
- b)[Mn(CO)5]–
- c)[Mn(CO)5]+
- d)Mn(CO)5
Correct answer is option 'D'. Can you explain this answer?
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Among the following, the unstable carbonyl species is:a)Mn(CO)5Clb)[Mn...
Unstable Carbonyl Species
Unstable carbonyl species are those compounds that have a tendency to lose carbon monoxide (CO) molecule easily.
Among the given options, the unstable carbonyl species is Mn(CO)5.
Explanation:
a) Mn(CO)5Cl: This compound contains a chloride ion coordinated with manganese pentacarbonyl. The chloride ion stabilizes the compound and prevents the loss of a CO molecule.
b) [Mn(CO)5]+: This is a cationic species and has a positive charge on the manganese atom. The positive charge stabilizes the compound and prevents the loss of a CO molecule.
c) [Mn(CO)5]-: This is an anionic species and has a negative charge on the manganese atom. The negative charge stabilizes the compound and prevents the loss of a CO molecule.
d) Mn(CO)5: This is the neutral form of manganese pentacarbonyl. The compound has a high tendency to lose a CO molecule and form Mn(CO)4. This reaction is exothermic and releases energy. Therefore, Mn(CO)5 is an unstable carbonyl species.
Conclusion:
Among the given options, Mn(CO)5 is the unstable carbonyl species because it has a high tendency to lose a CO molecule and form Mn(CO)4. The other options contain ions or ligands that stabilize the compound and prevent the loss of CO molecules.
Unstable carbonyl species are those compounds that have a tendency to lose carbon monoxide (CO) molecule easily.
Among the given options, the unstable carbonyl species is Mn(CO)5.
Explanation:
a) Mn(CO)5Cl: This compound contains a chloride ion coordinated with manganese pentacarbonyl. The chloride ion stabilizes the compound and prevents the loss of a CO molecule.
b) [Mn(CO)5]+: This is a cationic species and has a positive charge on the manganese atom. The positive charge stabilizes the compound and prevents the loss of a CO molecule.
c) [Mn(CO)5]-: This is an anionic species and has a negative charge on the manganese atom. The negative charge stabilizes the compound and prevents the loss of a CO molecule.
d) Mn(CO)5: This is the neutral form of manganese pentacarbonyl. The compound has a high tendency to lose a CO molecule and form Mn(CO)4. This reaction is exothermic and releases energy. Therefore, Mn(CO)5 is an unstable carbonyl species.
Conclusion:
Among the given options, Mn(CO)5 is the unstable carbonyl species because it has a high tendency to lose a CO molecule and form Mn(CO)4. The other options contain ions or ligands that stabilize the compound and prevent the loss of CO molecules.
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Community Answer
Among the following, the unstable carbonyl species is:a)Mn(CO)5Clb)[Mn...
AC. to EAN rule option a) follow EAN rule
boz Mn 7 e- +5*2 -1 = 16
b) also follow EAN having 18e_
c) also follow EAN having 16e-
d) doesn't follow EAN only having 17e- which are more unstable than another option
boz Mn 7 e- +5*2 -1 = 16
b) also follow EAN having 18e_
c) also follow EAN having 16e-
d) doesn't follow EAN only having 17e- which are more unstable than another option
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Among the following, the unstable carbonyl species is:a)Mn(CO)5Clb)[Mn(CO)5]–c)[Mn(CO)5]+d)Mn(CO)5Correct answer is option 'D'. Can you explain this answer?
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