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Let C be the circle x2 + y2 + 4x - 6y - 3 = 0 and L be the locus of the point of intersection of a 2 pair of tangents to C with the angle between the two tangents equal to 60°. Then, the point at which I touches the line x = 6 is
  • a)
    (6,4)
  • b)
    (6,8)
  • c)
    (6,3)
  • d)
    (6,6)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Let C be the circle x2 + y2 + 4x - 6y - 3 = 0 and L be the locus of t...
Explanation:

Given:
- Circle C: x^2 + y^2 + 4x - 6y - 3 = 0
- Locus L: Intersection of a pair of tangents to C with an angle of 60 degrees
- Point of tangency I touches the line x = 6

Finding the Point of Tangency:
1. Substitute x = 6 into the equation of circle C to find the y-coordinate of the point of tangency.
2. x = 6 gives us: 6^2 + y^2 + 4(6) - 6y - 3 = 0
3. Simplifying the equation gives: y^2 - 6y + 6 = 0
4. Solving the quadratic equation gives: y = 3 or y = 3
5. So, the point of tangency is (6, 3).
Therefore, the correct answer is option (c) (6, 3).
Free Test
Community Answer
Let C be the circle x2 + y2 + 4x - 6y - 3 = 0 and L be the locus of t...

This is the equation of a circle with radius 4 units and centered at (-2, 3)
From a point L we drop two tangents on the circle such that the angle between the tangents is 60o.

∠LPO = 90∘ 
∠PLO=30
 
Therefore the locus of the point L, is a circle centered at (-2, 3) and has a radius of (4 + x = 8) units.
The equation of this locus is thus, (x + 2)2 +(y − 3)2 = 82
 When x = 6, we have, (8)2 +(y − 3)2 = 82   , that is y = 3
The circle , (x + 2)2 +(y − 3)2 = 82, touches the line x = 6 at (6, 3).
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Let C be the circle x2 + y2 + 4x - 6y - 3 = 0 and L be the locus of the point of intersection of a 2 pair of tangents to C with the angle between the two tangents equal to 60°. Then, the point at which I touches the line x = 6 isa)(6,4)b)(6,8)c)(6,3)d)(6,6)Correct answer is option 'C'. Can you explain this answer?
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