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A body of mass 2 kg has an initial velocity of 3 metres per second along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body from O after 4 seconds will be
- a)12 m
- b)20 m
- c)8 m
- d)48 m
Correct answer is option 'B'. Can you explain this answer?
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A body of mass 2 kg has an initial velocity of 3 metres per second alo...
Given data:
- Mass of the body (m) = 2 kg
- Initial velocity (u) = 3 m/s
- Force applied (F) = 4 N
- Time duration (t) = 4 seconds
Calculating the acceleration:
- Since the force is perpendicular to the initial velocity, it will only cause a change in direction, not in magnitude.
- Therefore, the acceleration (a) can be calculated using the formula: F = ma
- Substituting the values, we get: 4 = 2a
- Thus, acceleration (a) = 2 m/s^2
Calculating the final velocity:
- Using the equation of motion: v = u + at
- Substituting the values, we get: v = 3 + 2*4 = 11 m/s
Calculating the distance traveled:
- Using the equation of motion: s = ut + (1/2)at^2
- Substituting the values, we get: s = 3*4 + (1/2)*2*(4)^2 = 20 m
Therefore, the distance of the body from O after 4 seconds will be 20 meters. Hence, option B is the correct answer.
- Mass of the body (m) = 2 kg
- Initial velocity (u) = 3 m/s
- Force applied (F) = 4 N
- Time duration (t) = 4 seconds
Calculating the acceleration:
- Since the force is perpendicular to the initial velocity, it will only cause a change in direction, not in magnitude.
- Therefore, the acceleration (a) can be calculated using the formula: F = ma
- Substituting the values, we get: 4 = 2a
- Thus, acceleration (a) = 2 m/s^2
Calculating the final velocity:
- Using the equation of motion: v = u + at
- Substituting the values, we get: v = 3 + 2*4 = 11 m/s
Calculating the distance traveled:
- Using the equation of motion: s = ut + (1/2)at^2
- Substituting the values, we get: s = 3*4 + (1/2)*2*(4)^2 = 20 m
Therefore, the distance of the body from O after 4 seconds will be 20 meters. Hence, option B is the correct answer.
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A body of mass 2 kg has an initial velocity of 3 metres per second along OE and it is subjected to a force of 4 N in a direction perpendicular to OE. The distance of the body from O after 4 seconds will bea)12 mb)20 mc)8 md)48 mCorrect answer is option 'B'. Can you explain this answer?
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