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In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)
Correct answer is '5'. Can you explain this answer?
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In a vernier calliper, each cm on the main scale is divided into 20 eq...
Explanation:
Given data:
- Each cm on the main scale is divided into 20 equal parts.
- Tenth vernier scale division coincides with tenth main scale division.
Calculating the Vernier Constant:
- The main scale reading is the total number of divisions on the main scale up to the zero mark of the vernier scale.
- The vernier scale reading is the division on the vernier scale that exactly coincides with a division on the main scale.
- The least count of the vernier calliper is given by the formula:
Least Count = (Value of one main scale division) / (Total number of divisions on the vernier scale)
- Since the tenth vernier scale division coincides with the tenth main scale division, the least count is equal to 0.1 main scale division.
- Given that each cm on the main scale is divided into 20 equal parts, the value of one main scale division is 1/20 = 0.05 cm = 0.05 x 10 = 0.5 mm.
- Therefore, the least count is 0.5 mm / 10 = 0.05 mm = 0.05 x 10^-2 mm = 5 x 10^-2 mm.
- Hence, the value of the vernier constant is 5 x 10^-2 mm.
Given data:
- Each cm on the main scale is divided into 20 equal parts.
- Tenth vernier scale division coincides with tenth main scale division.
Calculating the Vernier Constant:
- The main scale reading is the total number of divisions on the main scale up to the zero mark of the vernier scale.
- The vernier scale reading is the division on the vernier scale that exactly coincides with a division on the main scale.
- The least count of the vernier calliper is given by the formula:
Least Count = (Value of one main scale division) / (Total number of divisions on the vernier scale)
- Since the tenth vernier scale division coincides with the tenth main scale division, the least count is equal to 0.1 main scale division.
- Given that each cm on the main scale is divided into 20 equal parts, the value of one main scale division is 1/20 = 0.05 cm = 0.05 x 10 = 0.5 mm.
- Therefore, the least count is 0.5 mm / 10 = 0.05 mm = 0.05 x 10^-2 mm = 5 x 10^-2 mm.
- Hence, the value of the vernier constant is 5 x 10^-2 mm.
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In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)Correct answer is '5'. Can you explain this answer?
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In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a vernier calliper, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with tenth main scale division, then the value of vernier constant will be .............. x 10-2 mm. (in integers)Correct answer is '5'. Can you explain this answer?.
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