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When a metallic surface is illuminated by a monochromatic light of wavelength λ, then the potential difference required to stop the ejection of electrons is 3V₀. When the same surface is illuminated by the light of wavelength 2λ, then the potential difference required to stop the ejection of electrons is V₀. Then for photoelectric effect, the threshold wavelength for the metal surface will be
  • a)
  • b)
    4λ/3
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
When a metallic surface is illuminated by a monochromatic light of wav...
Explanation:

Given:
- Potential difference for λ = 3V
- Potential difference for 2λ = V

Threshold wavelength:
- The threshold wavelength is the minimum wavelength of light required to eject electrons from a metal surface.
- It is given by the equation: λ0 = 2λ

Using the given information:
- For the wavelength λ, the potential difference is 3V
- For the wavelength 2λ, the potential difference is V
- The ratio of potential difference to the wavelength is constant for a metal surface.

Mathematically:
- V/λ = 3
- V/2λ = 1
- Dividing the two equations, we get: λ/2λ = 3/1
- λ = 2λ

Therefore, the threshold wavelength for the metal surface is 4λ.
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When a metallic surface is illuminated by a monochromatic light of wavelength λ, then the potential difference required to stop the ejection of electrons is 3V. When the same surface is illuminated by the light of wavelength 2λ, then the potential difference required to stop the ejection of electrons is V. Then for photoelectric effect, the threshold wavelength for the metal surface will bea)6λb)4λ/3c)4λd)8λCorrect answer is option 'C'. Can you explain this answer?
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