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A ball is dropped downwards. After 1 second another ball is dropped downwards from the same point. What is the distance between them after 3 seconds
- a)25 m
- b)20 m
- c)50 m
- d)9.8 m
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A ball is dropped downwards. After 1 second another ball is dropped do...
Given Data:
- Initial velocity of both balls = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
Calculations:
- Distance covered by the first ball in 3 seconds:
Using the kinematic equation:
Distance (S) = ut + (1/2)gt²
Where,
u = initial velocity = 0 m/s
t = time taken = 3 seconds
g = acceleration due to gravity = 9.8 m/s²
Substitute the values in the equation:
S1 = 0*3 + (1/2)*9.8*(3)²
S1 = 0 + 0.5*9.8*9
S1 = 0 + 44.1
S1 = 44.1 m
- Distance covered by the second ball in 3 seconds:
Since both balls are dropped from the same point, the distance covered by the second ball in 3 seconds will be the same as the first ball, which is 44.1 m.
- Distance between the two balls after 3 seconds:
The distance between the two balls after 3 seconds is the difference between the distances covered by the two balls.
Distance between the balls = S1 - S2
Distance between the balls = 44.1 - 44.1
Distance between the balls = 0 m
Therefore, the distance between the two balls after 3 seconds is 0 m.
- Initial velocity of both balls = 0 m/s
- Acceleration due to gravity (g) = 9.8 m/s²
Calculations:
- Distance covered by the first ball in 3 seconds:
Using the kinematic equation:
Distance (S) = ut + (1/2)gt²
Where,
u = initial velocity = 0 m/s
t = time taken = 3 seconds
g = acceleration due to gravity = 9.8 m/s²
Substitute the values in the equation:
S1 = 0*3 + (1/2)*9.8*(3)²
S1 = 0 + 0.5*9.8*9
S1 = 0 + 44.1
S1 = 44.1 m
- Distance covered by the second ball in 3 seconds:
Since both balls are dropped from the same point, the distance covered by the second ball in 3 seconds will be the same as the first ball, which is 44.1 m.
- Distance between the two balls after 3 seconds:
The distance between the two balls after 3 seconds is the difference between the distances covered by the two balls.
Distance between the balls = S1 - S2
Distance between the balls = 44.1 - 44.1
Distance between the balls = 0 m
Therefore, the distance between the two balls after 3 seconds is 0 m.
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A ball is dropped downwards. After 1 second another ball is dropped downwards from the same point. What is the distance between them after 3 secondsa)25 mb)20 mc)50 md)9.8 mCorrect answer is option 'A'. Can you explain this answer?
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