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A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?
- a)3 x 102 ppm
- b)6.5 m
- c)130 ppm Pb
- d)21 ppm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A sample of 300.0 g of drinking water is found to contain 38 mg Pb. Wh...
We use parts per million to express the concentrations of solutions that contain very, very small amounts, often called trace amounts, of a given solute.
More specifically, a solution's concentration in parts per millions tells you the number of parts of solute present for every
106 = 1,000,000
parts of solution. You can thus say that a 1 ppm solution will contain exactly 1 g of solute for every 106g of solution.
In your case, you know that you have
in exactly
300.0 g = 3.000 ⋅ 102g solution
This means that you can use this known composition as a conversion factor to scale up the mass of the solution to 106g
Since this represents the mass of lead present in exactly 106g of solution, you can say that the solution has a concentration of
in exactly
300.0 g = 3.000 ⋅ 102g solution
This means that you can use this known composition as a conversion factor to scale up the mass of the solution to 106g
Since this represents the mass of lead present in exactly 106g of solution, you can say that the solution has a concentration of
Most Upvoted Answer
A sample of 300.0 g of drinking water is found to contain 38 mg Pb. Wh...
We use parts per million to express the concentrations of solutions that contain very, very small amounts, often called trace amounts, of a given solute.
More specifically, a solution's concentration in parts per millions tells you the number of parts of solute present for every
10^6=1,000,000
parts of solution. You can thus say that a 1 ppm
solution will contain exactly 1 g of solute for every 10^6g of solution.
In this case, you know that you have
38 mg Pb x (1 g/10^3 mg) = 3.8 x 10^-2 g Pb
in exactly
300.0 g = 3.000 x 10^2 g solution
This means that you can use this known composition as a conversion factor to scale up the mass of the solution to
10^6 g solution x (3.8 x 10^-2 g Pb/3.000 x 10^2 g solution)
= 130 g solution
Since this represents the mass of lead present in exactly 10^6 g of solution, you can say that the solution has a concentration of:
concentration (ppm) = 130 ppm Pb
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Community Answer
A sample of 300.0 g of drinking water is found to contain 38 mg Pb. Wh...
Question Analysis:
We are given the mass of drinking water and the concentration of lead (Pb) in milligrams. We need to determine the concentration of lead in parts per million (ppm).
Given Data:
Mass of drinking water = 300.0 g
Concentration of Pb = 38 mg
Solution:
To find the concentration of lead in parts per million (ppm), we need to convert the concentration from milligrams (mg) to parts per million (ppm).
Conversion Formula:
1 ppm = 1 mg/L
Calculations:
Step 1: Convert the mass of drinking water from grams to liters.
- Since 1 gram of water is equal to 1 milliliter (ml), the volume of water is also 300.0 mL.
- To convert mL to L, divide by 1000: 300.0 mL ÷ 1000 = 0.3 L
Step 2: Convert the concentration of lead from milligrams (mg) to milligrams per liter (mg/L).
- The concentration is given as 38 mg in 300.0 g of water.
- To convert mg to mg/L, divide by the volume of water in liters: 38 mg ÷ 0.3 L = 126.67 mg/L
Step 3: Convert the concentration from milligrams per liter (mg/L) to parts per million (ppm).
- Since 1 ppm = 1 mg/L, the concentration of lead in parts per million is 126.67 ppm.
Answer:
Therefore, the concentration of lead in the drinking water is 130 ppm (option C).
We are given the mass of drinking water and the concentration of lead (Pb) in milligrams. We need to determine the concentration of lead in parts per million (ppm).
Given Data:
Mass of drinking water = 300.0 g
Concentration of Pb = 38 mg
Solution:
To find the concentration of lead in parts per million (ppm), we need to convert the concentration from milligrams (mg) to parts per million (ppm).
Conversion Formula:
1 ppm = 1 mg/L
Calculations:
Step 1: Convert the mass of drinking water from grams to liters.
- Since 1 gram of water is equal to 1 milliliter (ml), the volume of water is also 300.0 mL.
- To convert mL to L, divide by 1000: 300.0 mL ÷ 1000 = 0.3 L
Step 2: Convert the concentration of lead from milligrams (mg) to milligrams per liter (mg/L).
- The concentration is given as 38 mg in 300.0 g of water.
- To convert mg to mg/L, divide by the volume of water in liters: 38 mg ÷ 0.3 L = 126.67 mg/L
Step 3: Convert the concentration from milligrams per liter (mg/L) to parts per million (ppm).
- Since 1 ppm = 1 mg/L, the concentration of lead in parts per million is 126.67 ppm.
Answer:
Therefore, the concentration of lead in the drinking water is 130 ppm (option C).
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A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer?.
A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sample of 300.0 g of drinking water is found to contain 38 mg Pb. What this concentration in parts per million?a)3 x 102ppmb)6.5 mc)130 ppm Pbd)21 ppmCorrect answer is option 'C'. Can you explain this answer?.
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