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There are two bodies X and Y with equal kinetic energy but different masses m and 4m respectively. The ratio of their linear momentum is-
  • a)
    1:2
  • b)
    4:1
  • c)
    1:√2
  • d)
    1:4
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
There are two bodies X and Y with equal kinetic energy but different m...
X and Y have equal kinetic energy but their masses are m and 4m respectively.
► 1/2 m1v12 = 1/2 m2v22  
► mv12 = 4m * v22  
► v1 : v2 = 2 : 1
Hence the ratio of their linear momentum is:
m1v1 : m2v2 = m * 2v : 4m * v = 1 : 2
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Community Answer
There are two bodies X and Y with equal kinetic energy but different m...
Kinetic energy E=1/2 mv^2 now, from here we can derive linear momentum i.e. P=mv=√(2mE) so, P1/ P2 = √(m1/m2)= √ (m/4m)=√1/4=1/2
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