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A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block is
- a)5 kN
- b)20 kN
- c)15 kN
- d)10 kN
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. T...
Concept:
When the density of the body is less than that of the water, it floats. According to Archimedes' principle the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.
For floating bodies, the weight of the body = buoyancy force
Weight of the body = Immersed volume x Unit weight of water.
Calculations:
Given,
L = 2m, B = 1 m, h = 1 m, γ = 10 kN/m3, d = 0.5 m
Weight of body = Buoyancy Force
Buoyancy (B) = Immersed volume × Unit weight of water
W = L x B x d × γ
W = 2 x 1 x 0.5 × 10 = 10 kN
Most Upvoted Answer
A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. T...
- Given Data:
The dimensions of the rectangular block are:
Length (l) = 2 m
Width (b) = 1 m
Depth (h) = 1 m
Depth of immersion (d) = 0.5 m
Density of water (ρ) = 10 kN/m3
- Weight of the block:
The weight of the block can be calculated using the formula:
Weight = Volume * Density * g
where,
g = acceleration due to gravity = 9.81 m/s2
- Volume of the block:
The volume of the block can be calculated as:
Volume = l * b * h
Volume = 2 * 1 * 1
Volume = 2 m3
- Volume of water displaced:
The volume of water displaced is equal to the volume of the immersed part of the block, which is:
Volume = l * b * d
Volume = 2 * 1 * 0.5
Volume = 1 m3
- Upthrust force:
The upthrust force acting on the block is equal to the weight of the water displaced, which can be calculated as:
Upthrust = Volume * Density * g
Upthrust = 1 * 10 * 9.81
Upthrust = 98.1 N
- Weight of the block in water:
The weight of the block in water will be equal to the weight of the block minus the upthrust force, which is:
Weight = Volume * Density * g - Upthrust
Weight = 2 * 10 * 9.81 - 98.1
Weight = 196.2 - 98.1
Weight = 98.1 N
Therefore, the weight of the block is 98.1 N, which is equivalent to 9.81 kN. However, the weight of the block is typically given in kN, so the answer would be 10 kN.
The dimensions of the rectangular block are:
Length (l) = 2 m
Width (b) = 1 m
Depth (h) = 1 m
Depth of immersion (d) = 0.5 m
Density of water (ρ) = 10 kN/m3
- Weight of the block:
The weight of the block can be calculated using the formula:
Weight = Volume * Density * g
where,
g = acceleration due to gravity = 9.81 m/s2
- Volume of the block:
The volume of the block can be calculated as:
Volume = l * b * h
Volume = 2 * 1 * 1
Volume = 2 m3
- Volume of water displaced:
The volume of water displaced is equal to the volume of the immersed part of the block, which is:
Volume = l * b * d
Volume = 2 * 1 * 0.5
Volume = 1 m3
- Upthrust force:
The upthrust force acting on the block is equal to the weight of the water displaced, which can be calculated as:
Upthrust = Volume * Density * g
Upthrust = 1 * 10 * 9.81
Upthrust = 98.1 N
- Weight of the block in water:
The weight of the block in water will be equal to the weight of the block minus the upthrust force, which is:
Weight = Volume * Density * g - Upthrust
Weight = 2 * 10 * 9.81 - 98.1
Weight = 196.2 - 98.1
Weight = 98.1 N
Therefore, the weight of the block is 98.1 N, which is equivalent to 9.81 kN. However, the weight of the block is typically given in kN, so the answer would be 10 kN.
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A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer?
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A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer?.
A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rectangular block 2 m long, 1 m wide and 1 m deep floats in water. The depth of immersion is 0.5 m. If water weighs 10 kN/m3. Then the weight of the block isa)5 kNb)20 kNc)15 kNd)10 kNCorrect answer is option 'D'. Can you explain this answer?.
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