EmSAT Achieve Exam > EmSAT Achieve Questions > A vertical gate closes a horizontal tunnel 4 ...
Start Learning for Free
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3 , g = 9.81 m/s2]
- a)5/27 m below the centroid of gate
- b)2/27 m below the centroid of gate
- c)1/27 m below the centroid of gate
- d)4/27 m below the centroid of gate
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide runni...
Concept:
Pressure intensity is given as, P = ρgh
The height of the imaginary free surface of the water above the bottom of the gate equivalent to a pressure intensity of 196.2 kN/m2 is, 
The total pressure on gate is, P = wAx̅
Where, A = area of gate, x̅ = vertical distance of CG from free surface
Vertical distance of CP from free surface is,
Where, IG = MOI at the center of axis,
Calculation:
Given:
ρ = 1000 kg/m3, g = 9.81 m/s2, A = 4 × 4, θ = 90°, P = 196.2 kN/m2.
The height of the imaginary free surface of the water,
The total pressure on gate is, P = wAx̅
Vertical distance of CG from free surface, x̅ = 20 - 2 = 18 m
Vertical distance of CP from free surface is,
The location of center of pressure below the centroid of gate is,
y = h - x̅
Most Upvoted Answer
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide runni...
Given data:
- Water height (h): 4 m
- Water width (b): 4 m
- Pressure at the bottom of the gate (P): 196.2 kN/m^2
- Density of water (ρ): 1000 kg/m^3
- Acceleration due to gravity (g): 9.81 m/s^2
Calculating the location of the center of pressure:
- The location of the center of pressure (h_c) can be calculated using the formula: h_c = h/3
Substitute the given values:
- h = 4 m
- h_c = 4/3 = 1.33 m
Converting the pressure from kN/m^2 to N/m^2:
- 196.2 kN/m^2 = 196.2 * 1000 N/m^2 = 196200 N/m^2
Calculating the force exerted on the gate:
- F = P * b * h = 196200 * 4 * 4 = 3139200 N
Calculating the location of the center of pressure:
- h_c = h/3 = 4/3 = 1.33 m
Converting the force to a point load:
- P = F/(b * h) = 3139200/(4 * 4) = 196200 N/m^2
Therefore, the location of the center of pressure is 2/27 m below the centroid of the gate.
- Water height (h): 4 m
- Water width (b): 4 m
- Pressure at the bottom of the gate (P): 196.2 kN/m^2
- Density of water (ρ): 1000 kg/m^3
- Acceleration due to gravity (g): 9.81 m/s^2
Calculating the location of the center of pressure:
- The location of the center of pressure (h_c) can be calculated using the formula: h_c = h/3
Substitute the given values:
- h = 4 m
- h_c = 4/3 = 1.33 m
Converting the pressure from kN/m^2 to N/m^2:
- 196.2 kN/m^2 = 196.2 * 1000 N/m^2 = 196200 N/m^2
Calculating the force exerted on the gate:
- F = P * b * h = 196200 * 4 * 4 = 3139200 N
Calculating the location of the center of pressure:
- h_c = h/3 = 4/3 = 1.33 m
Converting the force to a point load:
- P = F/(b * h) = 3139200/(4 * 4) = 196200 N/m^2
Therefore, the location of the center of pressure is 2/27 m below the centroid of the gate.
|
Explore Courses for EmSAT Achieve exam
|
|
Similar EmSAT Achieve Doubts
Top Courses for EmSAT AchieveView all
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer?
Question Description
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer?.
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? for EmSAT Achieve 2025 is part of EmSAT Achieve preparation. The Question and answers have been prepared according to the EmSAT Achieve exam syllabus. Information about A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for EmSAT Achieve 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for EmSAT Achieve.
Download more important topics, notes, lectures and mock test series for EmSAT Achieve Exam by signing up for free.
Here you can find the meaning of A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A vertical gate closes a horizontal tunnel 4 m high and 4 m wide running full with water. The pressure at the bottom of the gate is 196.2 kN/m2. What will be the location of center of pressure? [ρ = 1000 kg/m3, g = 9.81 m/s2]a)5/27 m below the centroid of gateb)2/27 m below the centroid of gatec)1/27 m below the centroid of gated)4/27 m below the centroid of gateCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice EmSAT Achieve tests.
|
|
Explore Courses for EmSAT Achieve exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup